Prime Time Practice Answers - West Linn

1 1 Pearson Education, Inc., publishing as Pearson Prentice Hall. All rights 1 AdditionalPractice1. ; since 2 and 5 are factors of 10, anynumber that has 10 as a factor must alsohave 5 as a ; for example, the number 35 has 7 as afactor, but since it is an odd number itdoes not have 2 as a factor. 2 and 7 areboth Prime factors of 14; for a number tobe a factor of 2 and 7, it would also be afactor of and 30, which have a product of 29 30 = two numbers give the largestproduct because they are the , 2, 3, 5, 6, 10, 15, 29, 30, 58, 87, 145, 174,290, 435 One way to find the factors is to testfactors below 29 to identify factor know that 29 30 870 so themiddle factor pair is 29 will vary, but the following areexamples of correct 5 10 3 3 116.

2 , 5, answer: 2, 8, 14 and 3, 12, many7. 4 24; 4 6 24; 24 6 4;24 4 12 96; 12 8 96; 96 12 8;96 8 12; 3 32 96; 32 3 96;96 32 3; 96 3 18 108; 18 6 108; 108 6 18; 108 18 6; 4 27 108; 27 4 108; 108 4 27; 108 27 4;9 12 108; 12 9 108; 108 9 12; 108 12 number is called a factor when it ismultiplied by another number to find aproduct. A number is called a divisor ofa number when it divides the dividendevenly to find a : Factors, Multiples, , 2, 3, 4, 6, , 3, 5, 9, 15, , , 2, 3, 6, 9, 18, 27, , 2, 3, 4, 6, 8, 12, 16, 24, , 2, 4, 5, 10, 20, 25, 50, , 3, 9, 13, 39, , 59, 61, 67, 71, 73 Investigation 2 dimensions are 3 8. The possibledimensions are 1 24, 2 12, 3 8, and 4 6.

3 Only the 3 8 rectangle hasdimensions with a sum of dimensions are 3 16. The possibledimensions are 1 48, 2 24, 3 16,4 14, and 6 8. Only the 3 16rectangle has dimensions with a sum thatis a Prime 56, 2 28, 4 14, 7 42, 2 21, 3 14, 6 80, 2 40, 4 20, 5 16, 8 75, 3 25, 5 108, 2 54, 3 36, 4 27, 6 18,9 225, 3 75, 5 45, 15 s number is 18 since the factorpairs 1 18, 2 9, and 3 6 have therequired sums and 18 < order to determine the number of tilesin each of the rectangles, multiply the tilesalong the length by the tiles on the time Practice Answers2 Pearson Education, Inc., publishing as Pearson Prentice Hall. All rights is the only number in the intersectionsince 13 is a Prime will vary; examples includefactors of two different Prime numbers( , 5 and 13) or factors of twodifferent relatively Prime numbers ( ,11 and 14).

4 7. numbers in the intersection arethe multiples of 10, which is 5 number that is a multiple of 10 must have 5 and 2 as factors since 5 2 would be placed with the multiplesof 5 since it is a multiple of 5 but not amultiple of 2. 90 would be placed in theintersection since it is a multiple ofboth 5 and fourth number is even. Since the firstthree numbers were even, odd, and odd,respectively, the sum of these three will beeven. Thus, an even number must beadded to this even sum to produce aneven 3 AdditionalPractice1. shouldn t have to wait at #14 bus should arrive at the mallat 10 the #11 bus shouldleave the mall for the museum atabout 10 (since the #11 bus runsevery 12 minutes, it leaves at the top ofevery hour).

5 Will have to wait 12 minutesbecause the #14 bus should arrive buses are at the mall at 9 ,10 , 11 , and noon because theleast common multiple of 15 and 12 rectangle is made with 42 tiles, andthe other is made with 56 tiles. Theseare the only two even multiples of 7 between 40 and rectangle with 42 tiles has a lengthof 6, and the rectangle with 56 tiles has alength of 8. These Answers are found byfinding the other number in the factorpair with 7 for each Answers will vary. For 42: 1 42, 2 21, or 3 14. For 56: 1 56, 2 28, or 4 will only have a conflict one day permonth on the least commonmultiple of 3 and 7 is 21. The nextcommon multiple, 42, is greater than thenumber of days in a the numbers are Prime , they don thave any proper factors other than , their least common multiplewould be their time Practice Answers10 Factors of 12 Factors of 13155248121436113911710203040 Multiples of 5 Multiples of 2155352524681218283234363822242614163 Pearson Education, Inc.

6 , publishing as Pearson Prentice Hall. All rights the numbers are Prime , the onlyfactors each number has is 1 and , the greatest common factormust be : 24; GCF: : 105; GCF: : 187; GCF: : 108; GCF: (b) and (c); for part (b), the twonumbers are relatively Prime . For part(c), the two numbers are greatest common factor of twonumbers is one of the two numberswhen the smaller number is a factor ofthe larger : Least Common 1:30 : Greatest Common 4 AdditionalPractice1. 2 3 3 5 2 2 2 2 3 ,011 337 7 is 5, LCM 27, LCM 9, LCM ; an odd number cannot have a factorof 2, and 3, 5, and 7 are the only threeprimes with a product less than ,8006.

7 Answer: 6 and 36 answer 12 and least common multiple is the othernumber in the ,the only common factor they haveis ,the only common factor they haveis , even numbers always have a factorof sure that all the factors of thesecond number differ from the first(except for 1). Prime time Practice AnswersMaze 92423726 Enter271154910 ExitMaze 1,08028 6 327 Enter57225 2 9 ExitMaze 38,220143970917 Enter220 604215229826137 ExitMaze 210310 3142 Enter357352 1052715 6 3 Exit4 Pearson Education, Inc., publishing as Pearson Prentice Hall. All rights : Prime ; 2; ; 5; 3; ; 2; 2; 3; ; 2; 3; 5; 2 2 3 2 2 5 , , ways; 2 groups of 16, 4 groups of 8,8 groups of 4, 16 groups of ?

8 3 ? ?32? ?32? packages of hot dogs, 2 packages of ,700 and 2,550 Investigation 5 with the number 1, repeatedlymultiply by 3 until the result exceeds1,000. The numbers would be 3, 9, 27, 81,243, multiplying terms by 5 andthen 3. In other words, multiply thefirst term by 5 to get the second term,multiply the second term by 3 to getthe third, multiply the third term by 5to get the fourth, multiply the fourthterm by 3 to get the fifth, and so ,375 and 10, greatest common factor is 3, sinceit is the first term in the sequence and aprime 1, 2, and 44. 1, largest Prime desert less than 50 is{24, 25, 26, 27, 28}.6. 5 10 2107. 2 5 11 3 5 2 7 29 Prime time Practice Answers