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Solving Multi-Step Equations

M 924021A1G JKvuBtsag CSkosfatEwPasr5ee r 2 AflJlB gryiBgThztEs2 P dMfa8d4ei uwRiut2hX nIBnIffiqnViMtaeh DA8lGgQelbzr6a1 by Kuta Software LLCKuta Software - Infinite Algebra 2 Name_____ Period____Date_____Solving Multi-Step EquationsSolve each ) 4 n 2 n = 42) 12 = 2 + 5 v + 2 v 3) 3 = x + 3 5 x 4) x + 3 3 = 65) 12 = 3 2 k 3 k 6) 1 = 3 r + 2 r 7) 6 = 3( x + 2)8) 3( 4 r 8) = 369) 24 = 6( x 3)10) 75 = 3( 6 n 5)-1- 3 y240u1v16 sKoudtNao qSUoqfGtAwAa0rYew e 5 Afl4ll WrHiqg0hAtnsC 2 GMxamdlei FwdiHtShd 4 IhnrfMiTnwiRtCe4 zAdlzgqexbprvaL by Kuta Software LLC11) 3( 1 + 6 r ) = 14 r 12) 6( 6 v + 6) 5 = 1 + 6 v 13) 4 k + 2( 5 k 6) = 3 k 3914) 16 + 5 n = 7( 6 + 8 n ) + 315) 10 p + 9 11 p = 2( 2 p + 4) 3( 2 p 2)16) 10 n + 3( 8 + 8 n ) = 6( n 4)17) 10( x + 3) ( 9 x 4) = x 5 + 318) 12( 2 k + 11) = 12( 2 k + 12)19) 12( x 12) = 9( 1 + 7 x )20) 11 + 10( p + 10) = 4 5( 2 p + 11)Critical thinking question:21) Explain two ways you could solve 20 = 5( 3 + x )-2- D 72g061U1

Solving Multi-Step Equations Date_____ Period____ Solve each equation. 1) 4 n − 2n = 4 2) −12 = 2 + 5v + 2v 3) 3 = x + 3 − 5x 4) x + 3 − 3 = −6 5) −12 = 3 − 2k − 3k 6) −1 = −3r + 2r 7) 6 = −3(x + 2) 8) −3(4r − 8) = −36 9) 24 = 6(−x − 3) 10) 75 = 3(−6n − 5)-1-

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Transcription of Solving Multi-Step Equations

1 M 924021A1G JKvuBtsag CSkosfatEwPasr5ee r 2 AflJlB gryiBgThztEs2 P dMfa8d4ei uwRiut2hX nIBnIffiqnViMtaeh DA8lGgQelbzr6a1 by Kuta Software LLCKuta Software - Infinite Algebra 2 Name_____ Period____Date_____Solving Multi-Step EquationsSolve each ) 4 n 2 n = 42) 12 = 2 + 5 v + 2 v 3) 3 = x + 3 5 x 4) x + 3 3 = 65) 12 = 3 2 k 3 k 6) 1 = 3 r + 2 r 7) 6 = 3( x + 2)8) 3( 4 r 8) = 369) 24 = 6( x 3)10) 75 = 3( 6 n 5)-1- 3 y240u1v16 sKoudtNao qSUoqfGtAwAa0rYew e 5 Afl4ll WrHiqg0hAtnsC 2 GMxamdlei FwdiHtShd 4 IhnrfMiTnwiRtCe4 zAdlzgqexbprvaL by Kuta Software LLC11) 3( 1 + 6 r ) = 14 r 12) 6( 6 v + 6) 5 = 1 + 6 v 13) 4 k + 2( 5 k 6) = 3 k 3914) 16 + 5 n = 7( 6 + 8 n ) + 315) 10 p + 9 11 p = 2( 2 p + 4) 3( 2 p 2)16) 10 n + 3( 8 + 8 n ) = 6( n 4)17) 10( x + 3) ( 9 x 4) = x 5 + 318) 12( 2 k + 11) = 12( 2 k + 12)19) 12( x 12) = 9( 1 + 7 x )20) 11 + 10( p + 10) = 4 5( 2 p + 11)Critical thinking question.

2 21) Explain two ways you could solve 20 = 5( 3 + x )-2- D 72g061U1Y 5 KUuPtxat nSTozfHtKw4aDrFey j uAxlFlH frziNgvhntwsf b gMdagdkeN Lw6ixtWhX CIenWf4ionPijt1eL TAHlWgferbUrTa0 by Kuta Software LLCKuta Software - Infinite Algebra 2 Name_____ Period____Date_____Solving Multi-Step EquationsSolve each ) 4 n 2 n = 4{2}2) 12 = 2 + 5 v + 2 v { 2}3) 3 = x + 3 5 x {0}4) x + 3 3 = 6{ 6}5) 12 = 3 2 k 3 k {3}6) 1 = 3 r + 2 r {1}7) 6 = 3( x + 2){ 4}8) 3( 4 r 8) = 36{5}9) 24 = 6( x 3){ 7}10) 75 = 3( 6 n 5){ 5}-1- O A2d0e141C eKtu2tmaJ lSpo3fLtowkaHrme7 y dA7lxl8 MrbirgphEt9sE 9 NMHaEdSeN HwWiJtahX SILn5f0iknJiutDeb aA8l3gXexbIrNaL by Kuta Software LLC11) 3( 1 + 6 r ) = 14 r { 1}12) 6( 6 v + 6) 5 = 1 + 6 v { 1}13) 4 k + 2( 5 k 6) = 3 k 39{ 3}14) 16 + 5 n = 7( 6 + 8 n ) + 3{1}15) 10 p + 9 11 p = 2( 2 p + 4) 3( 2 p 2){0}16) 10 n + 3( 8 + 8 n ) = 6( n 4){0}17) 10( x + 3) ( 9 x 4) = x 5 + 3{ 2}18) 12( 2 k + 11) = 12( 2 k + 12)No ) 12( x 12) = 9( 1 + 7 x ){ 3}20) 11 + 10( p + 10) = 4 5( 2 p + 11){ 7}Critical thinking question:21) Explain two ways you could solve 20 = 5( 3 + x )(1) Divide by 5 first, or (2) Distribute the 5 your own worksheets like this one with Infinite Algebra 2.

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