Term 1 Maths - VAGA Study

1 Chap 1 Real Numbers Page 1 For Solution of Question Click the Link in Pink ColourCHAPTER CHAPTER 11 REAL NUMBERS1. The sum of exponents of prime factors in the prime-factorisation of 196 is(a) 3(b) 4(c) 5(d) 2 SOL: The total number of factors of prime number is(a) 1(b) 0(c) 2(d) 3 SOL: The HCF and the LCM of 12, 21, 15 are respectively (a) 3, 140(b) 12, 420(c) 3, 420(d) 420, 3 SOL: The decimal representation of 25113# will(a) terminate after 1 decimal place(b) terminate after 2 decimal place(c) terminate after 3 decimal places(d) not terminateSOL: The LCM of smallest two digit composite number and smallest composite number is(a) 12(b) 4(c) 20(d) 44 SOL: HCF of two numbers is 27 and their LCM is 162.

2 If one of the numbers is 54, then the other number is(a) 36(b) 35(c) 9(d) 81 SOL: HCF of 144 and 198 is(a) 9(b) 18(c) 6(d) 12 SOL: 225 can be expressed as(a) 532#(b) 532#(c) 5322#(d) 533#SOL: The decimal expansion of 252352# will terminate after how many places of decimal?(a) 2(b) 4(c) 5 Buy hard book on amazon. For more details whatsapp at 8905629969 Page 2 Real Numbers Chap 1 For Solution of Question Click the Link in Pink Colour(d) 1 SOL: The decimal expansion of the rational number 125014587 will terminate after(a) one decimal place(b) two decimal places(c) three decimal places(d) four decimal placesSOL.

3 235 is(a) an integer(b) a rational number(c) an irrational number(d) a natural numberSOL: 23 is(a) an integer(b) a rational number(c) an irrational number(d) a whole numberSOL: For some integer q, every odd integer is of the form(a) q(b) q1+(c) q2(d) q21+SOL: If two positive integers a and b are written as axy32= and bxy3=, where x, y are prime numbers, then HCF ,ab^h is(a) xy(b) xy2(c) xy33(d) xy22 SOL: If two positive integers p and q can be expressed as pab2= and qab3=; where a, b being prime numbers, then LCM ,pq^h is equal to(a) ab(b) ab22(c) ab32(d) ab33 SOL: The values of x and y in the given figure are(a) 7, 13(b) 13, 7(c) 9, 12(d) 12, 9 SOL: If p1 and p2 are two odd prime numbers such that pp>12, then pp1222- is(a) an even number(b) an odd number(c) an odd prime number(d) a prime numberSOL: The rational number of the form qp, q0!

4 , p and q are positive integers, which represents .0 134 , ( ..) is(a) 999134 This PDF is review version of hard book available on Amazon. In hard book all solutions are given with 1 Real Numbers Page 3 For Solution of Question Click the Link in Pink Colour(b) 990134(c) 999133(d) 990133 SOL: Which of the following will have a terminating decimal expansion?(a) 21077(b) 3023(c) 441125(d) 823 SOL: If .x07=, then x2 is(a) .14(b) .15(c) .154(d) .145 SOL: Which of the following rational number have non-terminating repeating decimal expansion?(a) 312531(b) 51271(c) 20023(d) None of theseSOL: The number 331310- is divisible by(a) 2 and 3(b) 3 and 10(c) 2, 3 and 10(d) 2, 3 and 13 SOL: The least number which is a perfect square and is divisible by each of 16, 20 and 24 is(a) 240(b) 1600(c) 2400(d) 3600 SOL: n12- is divisible by 8, if n is(a) an integer(b) a natural number(c) an odd integer(d) an even integerSOL: When 2256 is divided by 17 the remainder would be(a) 1(b) 16(c) 14(d) None of theseSOL: Assertion : 312513 is a terminating decimal.

5 If q25mn= where ,mn are non-negative integers, then qp is a terminating decimal fraction.(a) Both assertion (A) and reason (R) are true and reason (R) is the correct explanation of assertion (A).(b) Both assertion (A) and reason (R) are true but reason (R) is not the correct explanation of assertion (A).(c) Assertion (A) is true but reason (R) is false.(d) Assertion (A) is false but reason (R) is : Assertion : is a terminating decimal : Denominator of , when expressed Buy hard book on amazon. For more details whatsapp at 8905629969 Page 4 Real Numbers Chap 1 For Solution of Question Click the Link in Pink Colourin the form qp, q0!

6 , is of the form 25mn#, where m and n are non-negative integers.(a) Both assertion (A) and reason (R) are true and reason (R) is the correct explanation of assertion (A).(b) Both assertion (A) and reason (R) are true but reason (R) is not the correct explanation of assertion (A).(c) Assertion (A) is true but reason (R) is false.(d) Assertion (A) is false but reason (R) is : Assertion : The HCF of two numbers is 5 and their product is 150, then their LCM is 30 Reason : For any two positive integers a and ,b,HCFab^h ,LCMab+^h ab#=.(a) Both assertion (A) and reason (R) are true and reason (R) is the correct explanation of assertion (A).

7 (b) Both assertion (A) and reason (R) are true but reason (R) is not the correct explanation of assertion (A).(c) Assertion (A) is true but reason (R) is false.(d) Assertion (A) is false but reason (R) is : a and b are two positive integers such that the least prime factor of a is 3 and the least prime factor of b is 5. Then the least prime factor of ()ab+ will be(a) 1(b) 2(c) 3 (d) 4 SOL: Select the least number that is divisible by all numbers between 1 and 10 (both inclusive).(a) 2520 (b) 5040(c) 1010 (d) 2020 SOL: The number 757 will have -(a) non-terminating repeating decimal expansion. (b) terminating decimal expansion.

8 (c) non-terminating non repeating decimal expansion.(d) terminating non repeating decimal expansionSOL: The decimal representation of 161521# will(a) terminate after 2 decimal place(b) terminate after 3 decimal place(c) terminate after 4 decimal places(d) terminate after 5 decimal placesSOL: The sum of exponents of prime factors in the prime-factorisation of 1764 is(a) 3(b) 4(c) 5(d) 6 SOL: In the given factor tree what is the composite number x?This PDF is review version of hard book available on Amazon. In hard book all solutions are given with 1 Real Numbers Page 5 For Solution of Question Click the Link in Pink Colour(a) 65 (b) 585(c) 130 (d) 195 SOL: The HCF and LCM of 378, 180 and 420 of will be(a) 6 and 3980(b) 12 and 3780(c) 6 and 3780(d) 12 and 3980 SOL: In the given factor tree what is the composite number x?

9 (a) 53 (b) 11130(c) 5565 (d) 19438 SOL: What is the HCF of smallest primer number and the smallest composite number?(a) 2 (b) 4(c) 6 (d) 8 SOL: If HCF(336, 54) 6=, LCM(336, 54) will be(a) 2024 (b) 3024(c) 1012 (d) 1512 SOL: What are the missing numbers c and d in the given factor tree:(a) 3 and 7 (b) 13 and 11(c) 6 and 9 (d) 5 and 4 SOL: hard book on amazon. For more details whatsapp at 8905629969 Page 6 Real Numbers Chap 1 For Solution of Question Click the Link in Pink ColourCOMPETENCEY BASED QUESTIONSD irection For Question : (40-41)When the marbles in a bag are divided evenly between two friends, there is one marble left over.

10 When the same marbles are divided evenly among three friends, there is one marble left over. When the marbles are divided evenly among five friends, there is one marble left What is the least possible number of marbles in the bag?(a) 31(b) 30(c) 32(d) 34 SOL: What is another possible number of marbles in the bag?(a) 31 (b) 61(c) 52 (d) 34 SOL: For Question : (42-45)An online shopping website sells 10 types of items which are packed into various sizes of cartons which are given below. Carton type Inner Dimensions (L # W)cm2 Small 6 # 8 Medium 12 # 24 Large 24 # 36 Extra large 36 # 48 XXL 48 # 96 The company places supporting thermocol sheets inside every package along the edges.