Transcription of TEXTBOOK SOLUTIONS
1 1 Teacher s Manual TEXTBOOK SOLUTIONS Exercise ..1 Exercise ..2 Exercise ..5 Exercise ..5 Exercise ..6 Exercise ..10 Exercise ..11 Exercise ..11 Exercise ..12 Exercise ..12 Exercise ..13 Exercise ..14 Exercise ..15 Exercise ..17 Exercise ..17 Exercise ..18 Exercise ..19 Exercise ..20 Exercise ..20 Exercise ..22 Exercise ..23 Exercise ..23 Exercise ..24 Exercise ..24 Exercise ..25 Exercise ..26 Exercise ..28 Exercise ..28 Exercise ..29 Exercise ..30 Exercise ..31 Exercise ..31 Exercise.
2 32 Exercise ..32 Exercise ..33 Exercise ..33 Exercise ..34 Exercise ..35 Exercise ..35 Exercise ..36 Exercise ..36 Exercise ..36 Exercise ..37 Exercise ..39 Exercise ..40 Exercise ..40 Exercise ..41 Exercise ..42 Exercise ..42 Exercise ..43 Exercise ..44 Exercise ..44 Exercise ..45 Exercise ..47 Exercise ..48 Exercise ..49 Exercise ..50 Exercise ..51 Exercise ..51 Exercise ..53 Exercise ..54 Exercise ..54 Exercise ..55 Exercise ..56 Exercise ..56 Exercise ..57 Exercise ..57 Exercise.
3 59 Exercise ..59 Exercise ..60 Exercise ..60 Exercise ..61 Exercise ..62 Exercise ..64 Exercise ..64 Exercise ..65 Exercise ..66 Exercise ..67 Exercise ..68 Exercise ..69 Exercise ..69 1 Teacher s Manual TEXTBOOK SOLUTIONSE xercise Q1 Area = length length Unit of area = (m)(m) = = the square metreQ2 = (Unit of m )(Unit of v ) = (kg)(m s 1 ) = kg m s 1 = the kilogram metre per secondQ3 Unit of a = = = m s 2 = the metre per second squaredQ4 kg m 3 , density = Unit of density = = kg m 3 Q5 P = Unit of P = = = Newton per square metre= N m 2 Q6 (a) 10 000 ( )(b) 1 000 000 ( )(c) 1000Q7 (i) 5 cm 2 = (ii) 40 cm 2 = = (iii) 1 cm 3 = (iv) 456 cm 3 = = (v)
4 1 000 000 000 = = Q8 (i) 105 km = = (ii) 57 mm = = (iii) = ( 10 2 )= (iv)grams = (10 3 ) kg= kg (v) 9 = = = kg m 3 (vi) 100 km h 1 = 100 000 m h 1 = m s 1 = m s 1 (vii) 5 nN = N (viii) 10 W = W = W (ix) 5 Gm = mQ9 Unit of force = (kg)(m s 2 ) 1 N = 1 kg m s 2 Q10 1 Joule = 1 N mQ11 1 J = 1 N m = 1(kg m s 2 )(m) = 1 kg m 2 s 2 Q12 1 W = 1 J s 1 = (1 kg m 2 s 2 )s 1 = 1 kg m 2 s 3m2 PmvUnit of p =Unit of vUnit of t----------------------m s1 s-------------MassVolume---------------- ---kgm3-------FA---Unit of ForceUnit of Area--------------------------------Newt onMetre squared--------------------------------- -100100 100100 100 5104 m240104 m24103 m21106 m3456106 m31109 ()106 103 m31000 m3=105103 m57103 () m61027 61027 ()
5 61024 gcm3---------9103 kg cm3----------------------------9103 1106 --------------------kgm3-------9103 100 0006060 -------------------5109 10106 1105 5109 Fma=WFs= real world Physics2 Exercise = = = sQ2 Incident ray, reflected ray, normal, angle of incidence, angle of = 1 m (see diagram)Q6 t = = = = yearsQ7 From the diagram (i) (ii) (iii) Q9 From the diagram, length = mExercise = 30v = 50f = ? + = + = = f = = length = cmQ2u = 20v = 30 Image virtual = = = = f = 60 cmQ3u = 15f = 10v = ?
6 + = + = = _ = = v = 30 cmImage is real (v + )Magnification = = = 2 Image is twice the size of object its height is 4 3108 3108 50 30 20 50 30 10 40 50 40 m1u---1v---1f---130------150------1f---5 3+150------------1f---1508---------1u--- 1v---1f---120------130------1f---32 60------------1f---1f---160------1u---1v ---1f---115------1v---110------1v---110- -----115------1v---32 30------------1v---130------vu---3015--- ---3 Teacher s ManualQ4u = 10f = 20v = ? + = + = = v = 20 cm Image is 20 cm from mirror.
7 It is = = = 2Q5f = 40 Magnification = 4 = v = 4u. Find u. + = + = = = f = 40 = u = u = 50 cmQ6(i) real image: + = = 3 v = 3u + = = = 3u = 80 u = 26 cm(ii) Virtual image = 3 and = v = +3u = = = u = = 13 cmQ7 real image: = 2 v = 2u + = + = = 2u = 150 u = 75 cmVirtual image: = 2 and = v = 2u = = u = 25 cmQ8 Image upright Virtual image = Magnification = 3 = = = 200 = 3uu = = 66 cmQ9 Image is real and at the focus since light from a distant object arrives as parallel = = u = 3v + = + = = v = u = 3v = 3 = 160 cm1u---1v---1f---110------1v---120------ 1v---120------110------vu---2010------vu ---1u---1v---1f---1u---14u------1f---41+ 4u------------1f---54u------1f---4u5---- --4u5------540
8 4---------------1u---1v---120------vu--- 1u---13u------120------31+3u------------ 120------43u------120------vu---1u---1v- --1f---1u---13u------120------31 3u------------120------23u------120----- -3u40=403------vu---1u---1v---1f---1u--- 12u------150------21+2u------------150-- ----vu---1u---1v---1f---1u---12u------15 0------21 2u------------150------2u50=1u---1v---1f ---vu---v3u=1u---13u------1100---------3 1 3u------------1100---------2003--------- 13---vu---13---1u---1v---1f---13v------1 v---140------43v------140------1603----- ----1603--------- real world Physics4 Exercise = m = u = 10, f = 12, v = ?
9 M = = = .545 = Image is virtual cm behind mirror. + = = = v = = cmQ2u = 30, f = 12, v = ? = = + = v = cmVirtualMagnification = = = = 10, Mag. = = 4v = u = = u = 4v = 30 = 4vu = 30 cm = v = cmQ4 = m = = v = 10m = = 2u = 5v = 2u = 5(10)u = 25 = = = f = = 16 cmQ5v = 4 cmhi = 4, ho = 6m = = = = u = 6 cm = = = = f = 12 cmQ6m = = = Find = = = = u = 40 cmQ7hi = ho = = u = 2v = = + = v = 20 u = 40 cmQ8m = = = v = = = f = u Object must be a distance in front of mirror equal to its focal + +34v------+110------14v------1v---110--- ---14 4v------------110------1u---1v---1f---vu ---Height of imageHeight of
10 Object---------------------------------- -----25---vu---1u---1v---1f---125------1 10------1f---25 50------------1f---3 50------1f---503------hiho-----vu---46-- -vu---46---4u---1u---1v---1f---16---14-- -1f---23 12------------1f---112------1f---vu---13 ---1u---1v---120------u3---1u---1u3---() -------120------1u---3u---120------2 u------120------hiho-----12---vu---12v-- ----1v---140------12 2v------------140------12v------140----- -12---vu---1u---1v---1f---u2---1u---1u2- --()-------1f---1u---1f---5 Teacher s ManualExercise = = = = = = = = Sin r = =.
