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Practice Problems: Integration by Parts (Solutions)

web.math.ucsb.edu

vtkala@math.ucsb.edu November 25, 2014 The following are solutions to the Integration by Parts practice problems posted November 9. 1. R exsinxdx Solution: Let u= sinx, dv= exdx. Then du= cosxdxand v= ex. Then Z exsinxdx= exsinx Z excosxdx Now we need to use integration by parts on the second integral.

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25Integration by Parts - University of California, Berkeley

math.berkeley.edu

Example C: ∫sin−1 x dx *At first it appears that integration by parts does not apply, but let: u =sin−1 x (Inverse Trig Function) dv =1 dx (Algebraic Function) dx x du 1 2 1

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Integration by parts - Mathematics resources

www.mathcentre.ac.uk

Integration by parts mc-TY-parts-2009-1 A special rule, integrationbyparts, is available for integrating products of two functions. This unit derives and illustrates this rule with a number of examples.

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INTEGRATION BY PARTS - Salford

www.cse.salford.ac.uk

Integration INTEGRATION BY PARTS Graham S McDonald A self-contained Tutorial Module for learning the technique of integration by parts Table of contents

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