Transcription of ANSWERS TO EVEN ASSIGNED PROBLEMS CHAPTER 12 …
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ANSWERS TO even ASSIGNED PROBLEMS CHAPTER 12 review (pages 723-724) the projection on theyzplane we can evaluate the integralas follows: EzdV= 10 1 y20 2 y0z dx dz dy= 10 1 y20(2 y)z dz dy= 1012(2 y)(1 y2)dy= 1012(2 y 2y2+y3)dy= spherical coordinates we have that 0 1(since the solid is bounded by the sphere of radius 1),0 2since the solid lies above thexyplane) and 0 le2 . Thus Hz3 x2+y2+z2dV= 2 0 /20 10( 3cos3 ) ( 2sin )d d d = 2 0d /20cos3 sin d 10 6d = 2 [ 14cos4 ] /20(17)= of the solid is the disk of radius 2 centered at theorigin. In cylindrical coordinates the planey+z= 3 has equationz= 3 rcos.
ANSWERS TO EVEN ASSIGNED PROBLEMS CHAPTER 12 REVIEW (pages 723-724) 26. x y z Using the projection on the yz plane we can evaluate the integral as follows: ZZZ E zdV = Z 1 0 Z p 1¡y2 0 Z 2¡y 0 z dx dz dy = Z 1 0 Z p 1¡y2 0
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CHAPTER 2: ANSWERS TO ASSIGNED PROBLEMS, College Physics 8th Edition by Serway, Answers, Answers to assigned problems, College Physics 8th Edition by, Vuille Answers to assigned problems, Assigned, Problems, Assigned problems, Answers to Assigned Odd-Numbered Text Problems for, Answers to Assigned Odd-Numbered Text Problems for Section, Answers to the Assigned Homework Problems, CCNA Practice Questions Exam 640-802, CCNA Practice Questions Exam 640–802, 35 Permutations, Combinations and Proba- bility, 35 Permutations, Combinations and Proba-bility