Transcription of Calculus 141, section 9.7 Alternating Series, Absolute ...
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Calculus 141, section 9.7 Alternating Series, Absolute ...
Calculus 141, section Alternating Series, Absolute Convergence notes by Tim Pilachowski So far, we have pretty much limited our attention to series which are positive. What can we say of those which . are not positive? We have taken a quick look at one Alternating series: ( 1)n diverges (Example C in lecture n =1. notes ) because the sequence of partial sums does not converge to a single value, but rather alternates between 1 and 0. The first question becomes: Can we determine whether an Alternating series is convergent or divergent? Theorem , credited to Leibniz, provides a straightforward test. To show that the Alternating . series ( 1)n an or ( 1)n+1 an converges, one need only to show that n =1 n =1.. the sequence {a n } is positive and decreasing, and that lim a n = 0 . n =1 n . Because the terms alternate in sign, the partial sums successively rise and . fall.
n diverges (Example C in lecture notes 9.4) because the sequence of partial sums does not converge to a single value, but rather alternates between −1 and 0.
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