Transcription of Ch 12 (26-2-2009)
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Ch 12 (26-2-2009)
(A) Main Concepts and Results The surface area of an object formed by combining any two of the basic solids,namely, cuboid, cone, cylinder, sphere and hemisphere. The volume of an object formed by combining any two of the basic solidsnamely, cuboid, cone, cylinder, sphere and hemisphere. The formulae involving the frustum of a cone are:(i)Volume of the frustum of the cone = 2212121[]3hrrrr ++(ii)Curved surface area of the frustum of the cone = (r1+r2)l,(iii)Total surface area of the frustum of the solid cone= l(r1+r2)+ 2212 +rr, where 2212( )=+lhrr,h = vertical height of the frustum, l = slant height of the frustum andr1 and r2 are radii of the two bases (ends) of the frustum. Solid hemisphere: If r is the radius of a hemisphere, thencurved surface area = 2 r2total surface area = 3 r2, and volume = 323 r Volume of a spherical shell = ()33124 3rr , where r1 and r2 are respectively itsexternal and internal this chapter , take 227 =, if not stated AREAS AND VOLUMESCHAPTER 1203/05/18 SURFACE AREAS AND VOLUMES137(B)Multiple Choice Questions :Choose the correct answer from the given four options:Sample Question 1 : A funnel (see ) is thecombination of(A) a cone and a cylinder
curved surface area = 2πr2 total surface area = 3πr2, and volume = 3 2 3 πr • Volume of a spherical shell = ()33 12 4 – 3 π rr, where r 1 and r 2 are respectively its external and internal radii. Throughout this chapter, take 22 7 π= , if not stated otherwise. SURFACE AREAS AND VOLUMES CHAPTER 12 03/05/18
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