Transcription of Chapter 5 The Second Law of Thermodynamics - CPP
{{id}} {{{paragraph}}}
Example: dental hygienist
Chapter 5 The Second Law of Thermodynamics - CPP
Chapter 5. The Second Law of Thermodynamics Statements of The Second Law Consider a power cycle shown in Figure that has the following characteristics. The power cycle absorbs 1000 kJ of heat from a high temperature heat source and performs 1200. kJ of work. Applying the first law to this system we obtain, Ecycle = Qcycle + Wcycle 0 = 1000 + ( 1200) = 200 kJ. This is obviously impossible and a clear violation of the first law of thermodyanmics as 200. kJ of energy have been created. High T High T. Qcycle = 1000 kJ Qcycle = 1000 kJ. System System Wcycle = 1200 kJ Wcycle = 1000 kJ. (a) Violation of the first law (b) Obey the first law Figure (a) A power cycle receiving 1000 kJ of heat and performing 1200 kJ of work, which is a violation of the law of conservation of energy. (b) A power cycle receiving 1000 kJ of heat and performing 1000 kJ of work, which does not violate the law of conservation of energy.
The Second Law of Thermodynamics 5.1 Statements of The Second Law Consider a power cycle shown in Figure 5.1-1a that has the following characteristics. The power cycle absorbs 1000 kJ of heat from a high temperature heat source and performs 1200 kJ of work. Applying the first law to this system we obtain, DE cycle = Q cycle + W
Tags:
Information
Domain:
Source:
Link to this page:
Please notify us if you found a problem with this document: