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Di erential Equations Water Tank Problems

Differential Equations Water Tank ProblemsChapter #3 VariationA tank originally contains 100 gal of fresh Water . Then Water containing12lb of salt per 2 gallonis poured into the tank at a rate of 2 gal/min, and the mixture is allowed to leave at the samerate. What is the amount of salt at any instant?dQdt= rate in - rate out= (salt concentration in) x (flow rate in) - (tank salt concentration) x (flow rate out)*NotedQdtshould be in terms oflbminParametersQ(t) : the amount of salt at time t (lbs)Qo: initial amount of salt in the tank Q(0) =Qo= 0salt concentration in =12lbgaltank salt concentration =Qcurrent amount of Water solution=Q100lbgalIn this question flow rate in is the same as flow rate out so we will let the rates be defined as.

Di erential Equations Water Tank Problems Chapter 2.3 Problem #3 Variation A tank originally contains 100 gal of fresh water. Then water containing 1 2 lb of salt per 2 gallon is poured into the tank at a rate of 2 gal/min, and the mixture is allowed to leave at the same

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  Water, Problem, Equations, Tanks, Erential, Di erential equations water tank problems

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