Transcription of INSERTS FOR PLASTICS
{{id}} {{{paragraph}}}
Example: bachelor of science
INSERTS FOR PLASTICS
LF = F x L INSERTS FOR PLASTICSP lasticInsertBoltFriction ForceForceLTo rqueF x LAxial Load(Tension)To rque = Coefficient of Friction =To rque x Bolt WHY INSERTS ? INSERTS provide reusable threads and secure tight threaded additional benefit is high load carrying LOAD CARRYINGThe load carrying ability of the joint is enhanced by the larger diameter of the Insert as compared to the screw. INSERTS are generally twice the diameter of the screw and that increases the shear surface fourfold. Pull-out resistance can further be enhanced by increased Insert BYSTRESS RELAXATIONA common problem with bolted joints in plastic applications is that plastic is susceptible to creep or stress relaxation. Under loads well below the elastic limit, PLASTICS will lose their ability to maintain a load.
the installation torque requirements to achieve a good threaded joint, and the pull-out values that meet the application load requirements. Helical knurls are the designer’s choice to maximize the torque resistance for a given diameter. The volume of these knurls must be such that sufficient
Loading..
Tags:
Information
Domain:
Source:
Link to this page:
Please notify us if you found a problem with this document: