Transcription of Lec7 Ch11 AcidBase Titn - Bridgewater State University
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Lec7 Ch11 AcidBase Titn - Bridgewater State University
1 Chapter 10 acid - base TITRATIONS1 Strong acid -Strong base TitrationsAbbreviationsExample:A mL solution of M NaOH is titrated with M HCl. Calculate the pH of solution at the following volumes of HCl added: 0, , Ve, and ++ OH-H2 OVa= volume of strong acid , volume of strong base , vol. titrant acid or base needed to reach the equivalence pointNet ionic equation:What is K for this reaction at 25 0C?K = 1/Kw Very large K; reaction goes to Titrations(Cont.)WORK:First you must determine VeSince the reaction stoichiometry is 1:1, mol H+= mol OH-At the equiv. ,Max Va= Mbx VbSince HCl is the titrant we substitute Vefor Va:Max Ve= Mbx VbAt the equiv. VbMaSubstituting the given quantities we get:Ve= {( mL)( M)} MVe= Titrations(Cont.)Calculate the solution pH at different Va sRegion 1: Before the equivalence point(WhenVa< Ve)(a) pH when Va= 0 What species is in solution?
1 Chapter 10 ACID-BASE TITRATIONS 1 Strong Acid-Strong Base Titrations Abbreviations Example: A 50.00 mL solution of 0.0100 M NaOH is …
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