Transcription of Table of Basic Integrals1
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Table of Basic Integrals1 . Z. 1 Z. (1) xn dx = xn+1 , n 6= 1 (11) sec2 x dx = tan x n+1. Z. 1. (2) dx = ln |x| Z. x (12) sec x tan x dx = sec x Z Z. (3) u dv = uv vdu Z. a x (13) dx = tan 1. a2 +x 2 a Z. (4) ex dx = ex Z a 1 x + a (14) dx = ln Z a2 x 2 2 x a 1 x (5) ax dx = a ln a Z. 1 x (15) dx = sin 1. a2 x 2 a Z. (6) ln x dx = x ln x x Z. a x Z (16) dx = sec 1. (7) sin x dx = cos x x x2 a2 a Z. Z 1 x (8) cos x dx = sin x (17) dx = cosh 1. x2 a 2 a . = ln(x + x2 a2 ). Z. (9) tan x dx = ln | sec x|. Z. 1 x (18) dx = sinh 1.
Table of Basic Integrals1 (1) Z xn dx = 1 n+1 xn+1; n 6= 1 (2) Z 1 x dx = lnjxj (3) Z u dv = uv Z vdu (4) Z e xdx = e (5) Z ax dx = 1 lna ax (6) Z lnxdx = xlnx x (7) Z sinxdx = cosx (8) Z cosxdx = sinx (9) Z tanxdx = lnjsecxj (10) Z secxdx = lnjsecx+tanxj (11) Z sec2 xdx = tanx (12) Z secxtanxdx = secx (13) Z a a2 +x2 dx = tan 1 x a (14) Z a a2 ...
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