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Chapter 15 Transformer Design

Chapter 15 Transformer Design

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Take derivatives of core and copper loss Now, substitute into and solve for B: Optimum B for a given core and application P cu = ρλ 1 2 I tot 2 4K u (MLT) W A A c 2 1 ∆B P 2 fe = K fe (∆B) βA c l m dP fe d(∆B) = βK fe (∆B) β–1A cl m dP cu d(∆B) =–2 ρλ 1 2I tot 2 …

  Core, Copper

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