LECTURE 2: COMPLEX DIFFERENTIATION AND CAUCHY
LECTURE 2: COMPLEX DIFFERENTIATION AND CAUCHY RIEMANN EQUATIONS 3 (1) If f : C → C is such that f0(z) = 0 for all z ∈ C, then f is a constant function. This is because, by CR equation u x = u y = v x = v y = 0. So by MVT of two variable calculus u and v are constant function and hence so is f.
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