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Math 127: Chinese Remainder Theorem - CMU

Math 127: Chinese Remainder Theorem - CMU

www.math.cmu.edu

Example 5. Use the Chinese Remainder Theorem to nd an x such that x 2 (mod5) x 3 (mod7) x 10 (mod11) Solution. Set N = 5 7 11 = 385. Following the notation of the theorem, we have m 1 = N=5 = 77, m 2 = N=7 = 55, and m 3 = N=11 = 35. We now seek a multiplicative inverse for each m i modulo n i. First: m 1 77 2 (mod5), and hence an inverse to m 1 ...

  Chinese, Math, Theorem, Remainder, Chinese remainder theorem, Math 127

Math 217: Summary of Change of Basis and All That

Math 217: Summary of Change of Basis and All That

www.math.lsa.umich.edu

2 of polynomials of degree 2 consists of all expressions of the form a+bx+cx2. Here, the choice of the basis f1;x;x2ggives an isomorphism identifying P 2 with R3: P 2!R3 a+bx+cx2 7! 2 4 a b c 3 5: The formal mathematical statement is that the mapping V !Rn ~x7![~x] B is an isomorphism of vector spaces.2 This is deeper than just matching up the ...

  Change, Summary, Math, Basis, Math 127, Summary of change of basis

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