Search results with tag "Calculations involving a limiting reactant"

3.10 Calculations Involving a Limiting Reactant

X 1 mol of NH Solution 3 17.0 g of NH 3 X 1 mol of N 2CH 4O 2 mol of NH 3 X = 9.03 grams of N 2CH 4O is the theoretical yield 60.1 g of N 2CH 4O % yield = Actual yield Theoretical yield X 100 = 3.12 g The actual yield was 3.12 g of N 2CH 4O, so the % yield is 9.03 g X 100 = 34.6%

  Involving, Calculation, Limiting, Reactants, Calculations involving a limiting reactant