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The Scalar Equation of a Plane - University of Waterloo

The cross product of these two vectors gives a vector that is perpendicular to both, and hence perpendicular to the plane (that is, a normal to the plane). (—7, 25, —2) Thus, the scalar equation of the plane is of the form —7m + 25y — 2z + D Substituting the point (1, 1, 0), we get o o The scalar equation of the plane is

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