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The Borel-Cantelli Lemma and its Applications
www.math.unm.edu2 The Borel-Cantelli lemma and applications Lemma 1 (Borel-Cantelli) Let fE kg1 k=1 be a countable family of measur-able subsets of Rd such that X1 k=1 m(E k) <1 Then limsup k!1 (E k) is measurable and has measure zero. Proof. Given the identity, E= limsup k!1 (E k) = \1 n=1 [1 k= E k Since each E k is a measurable subset of Rd, S 1
The Incenter/Excenter Lemma - Evan Chen
web.evanchen.ccmidpoint of arc BC. Show that L is the center of a circle through I, I A, B, C. A BC I L I A Proof. This is just angle chasing. Let A = \BAC, B = \CBA, C = \ACB, and note that A, I, L are collinear (as L is on the angle bisector). We are going to show that LB = LI, the other cases being similar. First, notice that \LBI = \LBC + \CBI = \LAC ...