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12 Math 51 Solve Equations with Radicals
III. This example will require you to square twice because there are two radicals in the problem. 3x− 2x−5=−2 ⇐ First, isolate one radical by adding 2x−5 to both sides. 3x= 2x−5−2 ⇐One radical is isolate so we square both sides. ( ) =( − − ) ⇒ 2 2 3x 2x 5 2 You must FOIL on the right ⇒ 3x=( 2x−5−2)( 2x−5−2)
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