Transcription of 2章 円管内圧力損失(5.1) - 谷口150624
1 2-1 2 1 m 31000kg/m 10 Pa s 1 m0/sQ R = 10-3 m R = 10-3 m 373233Re ( 10 2)[ 10 / ( 10 ) ] ( 10 ) 10 309 2100 373043488 ( 10 ) ( 10 ) ( 10Pa)LQLPPR 2 2max1xuuR max2uu < u > R = 10-3 m 21 10 m/suQR CFD x( ,0)yumax(0,0)(0, )2-2 < u > 2 (1) COMSOL Multiphysics (2) 2D 2-3 (3) 2-4 (4) 2-5 (1) (2) ( ) R [m] L [m] rho 1000[kg/m^3] myu [Pa*s] v_ave1 [m/s] v_ave2 [m/s] 2-6 (1) ( m ) 2-7 (2) ( ) R L ( R= 10 3 ) 2-8 (3) (4) 2-9 2-10 (1)
2 ( ) 2-11 (2) 1 2-12 (3) 2-13 (4) 1 2 1 1 ( ) 1 U0 2*v_ave1*(1 (1 s)^2) (R= 10 -3 U0=2*v_ave2*(1 (1 s)^2) ) s 1 built-in variables F1 2-14 (5) 3 0 Pa 2-15 (1) 1 3 (2) 1 ( ) 6 2-16 (1) 1 2-17 (1) (2D) 2-18 (2) (2D)1 Plot r z 1 0 2 2-19 (3) 1D (4) (1D ) 2D 1 ( 1D 4 4 ) 2-20 (5) 1D 4 (6) ( ) y = 2-21 (7) (2) (2D) 2D ( 2D)
3 Plot r z 1 0 0 2 0 2-22 (8) (3) 1D 1D ( 5) 2D 2 1D 5 2D 2 (9) (5) 1D 5 ( ) y p Plot 2-23 y p y ( ) (10) 6700 Pa 2-24 (11) R = 10-3m ( v_ave1 v_ave2 ) ( ) 418Pa
