Assignment 1 Exercise 1 - Chinese University of Hong Kong
1. Carefully derive the equation of a string in a medium in which the resistance is proportional to the velocity. 5. Derive the equation of one-dimensional di usion in a medium that is moving along the xaxis to the right at constant speed V. 6. Consider heat ow in a long circular cylinder where the temperature depends only on tand on the distance
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PROOF OF TAYLOR’S THEOREM
www.math.cuhk.edu.hkection on the proof(s) of Taylor’s theorem. First we recall the (derivative form) of the theorem: Theorem 1 (Taylor’s theorem). Suppose f: (a;b) !R is a function on (a;b), where a;b 2R with a < b. Assume that for some positive integer n, f is n-times di erentiable on the open interval
Chapter 3 The Space of Continuous Functions
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www.math.cuhk.edu.hk3.2. THE CONTRACTION MAPPING PRINCIPLE 3 This theorem will be further explained and proved in the appendix. 3.2 The Contraction Mapping Principle Solving an equation f(x) = 0;where f is a function from Rn to itself frequently comes up in application. This problem can be turned into a problem for xed points. Literally,
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www.math.cuhk.edu.hk1 Derivatives of Piecewise Defined Functions For piecewise defined functions, we often have to be very careful in com-puting the derivatives. The di↵erentiation rules (product, quotient, chain rules) can only be applied if the function is defined by ONE formula in a neighborhood of the point where we evaluate the derivative. If we want
MATH2060A Solution to Assignment 1
www.math.cuhk.edu.hkexamine the di erentiability of j at 0 using de niton. Indeed, using the fact the cosine function is even, lim h!0 cosjhj cos0 h 0 = lim h!0 cosh 1 h = 0; from which we conclude that jis also di erentiable at x= 0. Hence jis di erentiable everywhere. A shortcut is to realize that the cosine is an even function, so j(x) = cosxis dif-ferentiable ...
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www.math.cuhk.edu.hkIndeed, in MATH2060 we learned that if f is continuously di erentiable on (a;b) with non-vanishing f0, it is either strictly increasing or decreasing so that its global inverse exists and is again continuously di erentiable. Example 4.3. Consider the map F: R2!R2 given by F(x;y) = (x2;y). Its Jacobian matrix is singular at (0;0).
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