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Chapter 03 - Stoichiometry

1 Chapter 3: StoichiometryKey Skills: Balance chemical equations Predict the products of simple combination, decomposition, and combustion reactions. Calculate formula weights Convert grams to moles and moles to grams using molar masses. Convert number of molecules to moles and moles to number of molecules using Avogadro s number Calculate the empirical and molecular formulas of a compound from percentage composition and molecular weight. Identify limiting reactants and calculate amounts, in grams or moles, or reactants consumed and products formed for a reaction. Calculate the percent yield of a the study of the quantitativerelationships in substances and their reactions Chemical equations The mole and molar mass Chemical formulas Mass relationships in equations Limiting reactant2 Definitions Reactantsare the substances consumed Productsare the substances formed Coefficientsare numbers before the formula of a substance in an equation A balancedequation has the same number of atoms of each element on both sides of th

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Transcription of Chapter 03 - Stoichiometry

1 1 Chapter 3: StoichiometryKey Skills: Balance chemical equations Predict the products of simple combination, decomposition, and combustion reactions. Calculate formula weights Convert grams to moles and moles to grams using molar masses. Convert number of molecules to moles and moles to number of molecules using Avogadro s number Calculate the empirical and molecular formulas of a compound from percentage composition and molecular weight. Identify limiting reactants and calculate amounts, in grams or moles, or reactants consumed and products formed for a reaction. Calculate the percent yield of a the study of the quantitativerelationships in substances and their reactions Chemical equations The mole and molar mass Chemical formulas Mass relationships in equations Limiting reactant2 Definitions Reactantsare the substances consumed Productsare the substances formed Coefficientsare numbers before the formula of a substance in an equation A balancedequation has the same number of atoms of each element on both sides of the equationChemical Equations A chemical equation is a shorthand notation to describe a chemical reaction Just like a chemical formula.

2 A chemical equation expresses quantitative relations Subscripts tell the number of atoms of each element in a molecule Coefficients tell the number of molecules3 Hydrogen and oxygen can make water or hydrogen peroxide2 H2(g) + O2(g) 2 H2O(l)H2(g) + O2(g) H2O2(l)Coefficients vs. Subscripts 4 Anatomy of a Chemical EquationReactantsappear on the left side of the on the right side of the statesof the reactants and products are written in parentheses to the right of each element symbol or Balanced Equations Write the correct formula for each substanceH2+ Cl2 HCl Addcoefficients so the number of atoms of each element are thesame on both sides of the equationH2+ Cl2 2 HCl5 Balancing Chemical Equations Assume one molecule of the most complicated substanceC5H12+ O2 CO2+ H2O Adjust the coefficient of CO2to balance CC5H12+ O2 5CO2+ H2O Adjust the coefficient of H2O to balance HC5H12+ O2 5CO2+ 6H2O Adjust the coefficient of O2to balance OC5H12+ 8O2

3 5CO2+ 6H2O Check the balance by counting the number of atoms of each Equations Sometimes fractionalcoefficients are obtainedC5H10+O2 CO2+H2OC5H10+O2 5CO2+H2OC5H10+ O2 5CO2+5H2OC5H10+ (15/2)O2 5CO2+ 5H2O Multiply all coefficients by the denominator2 C5H10+ 15 O2 10 CO2+ 10 H2O6 CombinationDecompositionOne substance breaks down into two or more substances2 NaN3 (s) 2 Na(s) + 3 N2 (g)CaCO3 (s) CaO (s) + CO2 (g)2 KClO3 (s) 2 KCl(s) + O2 (g)7Is the process of burning, the combination of an organic substance with oxygen to produce a flame. When an organic compound burns in oxygen, the carbon reacts with oxygen to form CO2, and the hydrogen forms water, the following combustion reactions:C3H8+ O2 CO2+ H2O(C2H5)2O + O2 CO2+ H2 OCombustionFormula Weight (FW) Sum of the atomic weights for the atoms in a chemical formula The formula weight of calcium chloride, CaCl2, would beCa: 1( amu)+ Cl: 2( amu) amu Formula weights are generally reported for ioniccompounds8 Molecular Weight (MW) Sum of the atomic weights of the atoms in a molecule For the molecule ethane, C2H6, the molecular weight would beC: 2( amu)+ H.

4 6( amu) amuPercent CompositionOne can find the percentage of the mass of a compound that comes from each of the elements in the compound by using this equation:% element =(number of atoms)(atomic weight)(FW of the compound)x 100%9 Percent CompositionSo the percentage by mass of carbon in ethane (C2H6) =(2)( amu)( amu) amu=x 100= 100 The Mole One moleis the amount of substance that contains as many entities as the number of atoms in exactly 12 grams of the 12C isotope of carbon. Avogadro s numberis the experimentally determined number of atoms in 12 g of isotopically pure 12C, and is equal to x 1023 One mole of anything contains x 1023entities 1 mol H = x 1023atoms of H 1 mol H2= x 1023molecules of H2 1 mol CH4= x 1023molecules of CH4 1 mol CaCl2= x 1023formula units of CaCl210 Avogadro snumberMoles to Number of EntitiesMoles ofsubstanceNumber ofatoms or moleculesExample Calculations How many Na atoms are present in mol of Na?

5 How many moles of C2H6are present in x 1021molecules of C2H6? 11 Molar MassThe molar mass (M)of any atom, molecule or compound is the mass (in grams) of one mole of that molar massin grams is numerically equal to the atomic mass or molecular mass expressed in u (oramu).Atomic ScaleLab ScaleSubstanceNameMassMolar MassAratomic g/molNaFformula g/molWhat mass of compound must be weighed out, to have a molsample of H2C2O4(M= g/mol)?Oxalic acid12 Interconverting masses and number of formula unitsWhat is the mass of moles of CH4?4444CH g mol 1CH g mol Example CalculationEmpirical formulaExample 1: What is the empirical formula of a compound that contains g C and g H in a g sample?

6 Example 2: What is the empirical formula of a chromium oxide that is Cr by mass?13 Combustion Analysis Compounds containing C, H and O are routinely analyzed through combustion in a chamber like this C is determined from the mass of CO2produced H is determined from the mass of H2O produced O is determined by difference after the C and H have been determinedFinding C and H content A weighed sample of compound is burned, and the masses of H2O and CO2formed is Empirical FormulasAssuming g of para-aminobenzoic acid,C: g x = mol g x= mol HN: g x= mol NO: g x = mol O1 g1 g1 g1 gExample: The compound para-aminobenzoic acid (you may have seen it listed as PABA on your bottle of sunscreen) is composed of carbon ( ), hydrogen ( ), nitrogen ( ), and oxygen ( ).

7 Find the empirical formula of Empirical FormulasCalculate the mole ratio by dividing by the smallest number of moles:C:= 7H:= 7N:= := molC7H7NO215 Example CalculationA compound contains only C, H, and O. A g-sample burns completely in oxygen to form g water and g CO2. Calculate the mass of each element in this sample. What is the empirical formula of the compound?ComparisonFormula to mass percent Mass percent to formulaSubscripts informulaMasses of elements andcompoundPercentcompositionAtomic massesMass of element Mass of compoundx 100%Composition(mass or mass %)Molar massesof elementsMoles ofeach elementEmpiricalformulaDivide bysmallest number16 Mole Relationships in EquationsGuidelines for Reaction Stoichiometry Write the balanced equation.

8 Calculate the number of moles of the species for which the mass is given. Use the coefficients in the equation to convert the moles of the given substance into moles of the substance desired. Calculate the mass of the desired the reaction4 FeS2+ 11 O2 2Fe2O3+ 8SO2 What mass of SO2is produced from reaction of g of FeS2and excess O2?Example CalculationExample CalculationWhat mass of SO3forms from the reaction of g of SO2 with an excess of O2?18 Reaction YieldsActual yield is found by measuring the quantity of product formed in the yieldis calculated from reaction yield = Actual yieldTheoretical yield 100% Example: Calculating Percent YieldA g-sample of potassium bromide is treated with perchloric acid solution.

9 The reaction mixture is cooled and solid KClO4is removed by filtering, then it is dried and weighed. KBr (aq)+HClO4 (aq) KClO4 (s)+HBr (aq)The product weighed g. What was the percent yield?19 Limiting ReactantLimiting reactant: the reactant that is completely consumed in a reaction. When it is used up, the reaction stops, thus limiting the quantities of products reactant : the other reactants present, not completely consumed2H2(g) + O2(g) 2H2O(g)O2H2202H2(g) + O2(g) 2H2O(g)5[2H2(g) + O2(g) 2H2O(g)]10H2(g) + 5O2(g) 10H2O(g)2H2(g) + O2(g) 2H2O(g)5[2H2(g) + O2(g) 2H2O(g)]10H2(g) + 5O2(g) 10H2O(g)21 Strategy for Limiting ReactantMass of A(reactant)Mass of B(reactant)Moles of AMoles of BMoles ofProductMoles ofProductChoosesmalleramountMolar mass of AMolar mass of BCoefficients in the equationMolar mass of productMass ofproduct22 Example CalculationCalculate the theoretical yield (g) when g of N2 reacts with g of H2, forming reaction step in the conversion of ammonia to nitric acid involves converting NH3to NO by the following reaction.

10 4 NH3(g) + 5 O2(g) 4 NO(g) + 6 H2O(g)If g of NH3reacts with g O2, then:1. Which is the limiting reactant?2. How many grams of NO and H2O form?3. How many grams of the excess reactant remain after the limiting reactant is completely consumed?4. Do parts 1 and 2 obey the law of conservation of mass?Example Calculatio


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