Example: Is this matrix diagonalizable?
reduced row echelon form and writing a null space as a span. We have found only two linearly independent eigenvectors for A, namely the vectors 2 4 1 0 1 3 5and 2 4 8 0 1 3 5: But any basis for R3 consists of three vectors. Therefore there is no eigenbasis for A, and so by Proposition 23.2 matrix Ais not diagonalizable.
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