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Geometric Sequences - Alamo Colleges District

Geometric Sequences Another simple way of generating a sequence is to start with a number a and repeatedly multiply it by a fixed nonzero constant r . This type of sequence is called a Geometric sequence . Definition: A Geometric sequence is a sequence of the form 234,,,,, ..aarar ar ar The number a is the first term, and r is the common ratio of the sequence . The nth term of a Geometric sequence is given by 1nnaar =. The number r is called the common ratio because any two consecutive terms of the sequence differ by a multiple of r, and it is found by dividing any term 1na+ after the first by the preceding term.

Geometric Sequences . Another simple way of generating a sequence is to start with a number “a” and repeatedly multiply it by a fixed nonzero constant “r”.This …

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Transcription of Geometric Sequences - Alamo Colleges District

1 Geometric Sequences Another simple way of generating a sequence is to start with a number a and repeatedly multiply it by a fixed nonzero constant r . This type of sequence is called a Geometric sequence . Definition: A Geometric sequence is a sequence of the form 234,,,,, ..aarar ar ar The number a is the first term, and r is the common ratio of the sequence . The nth term of a Geometric sequence is given by 1nnaar =. The number r is called the common ratio because any two consecutive terms of the sequence differ by a multiple of r, and it is found by dividing any term 1na+ after the first by the preceding term.

2 That is na 1nnara+=. Is the sequence Geometric ? Example 1: Determine whether the sequence is Geometric . If it is Geometric , find the common ratio. (a) 2, 8, 32, 128, ..(b) 1 , 2, 3, 5, 8, .. Solution (a): In order for a sequence to be Geometric , the ratio of any term to the one that precedes it should be the same for all terms. If they are all the same, then r, the common difference, is that value. Step 1: First, calculate the ratios between each term and the one that precedes it. 8423248128432=== By: Crystal Hull Example 1 (Continued): Step 2: Now, compare the ratios.

3 Since the ratio between each term and the one that precedes it is 4 for all the terms, the sequence is Geometric , and the common ratio . 4r= Solution (b): Step 1: Calculate the ratios between each term and the one that precedes it. 211332255338855==== Step 2: Compare the ratios. Since they are not all the same, the sequence is not Geometric . Similar to an arithmetic sequence , a Geometric sequence is determined completely by the first term a, and the common ratio r. Thus, if we know the first two terms of a Geometric sequence , then we can find the equation for the nth term.

4 Finding the Terms of a Geometric sequence : Example 2: Find the nth term, the fifth term, and the 100th term, of the Geometric sequence determined by 16,3ar==. Solution: To find a specific term of a Geometric sequence , we use the formula for finding the nth term. Step 1: The nth term of a Geometric sequence is given by 1nnaar = So, to find the nth term, substitute the given values 16,3ar== into the formula. 1163nna = By: Crystal Hull Example 2 (Continued): Step 2: Now, to find the fifth term, substitute 5n= into the equation for the nth term.

5 5154163163681227a = = == Step 3: Finally, find the 100th term in the same way as the fifth term. 100 1599999816316323323a = = == Example 3: Find the common ratio, the fifth term and the nth term of the Geometric sequence . (a) 1, 9, 81, 729, .. (b) 231, ,,, ..2 6 18 54tt t Solution (a): In order to find the nth term, we will first have to determine what a and r are. We will then use the formula for finding the nth term of a Geometric sequence . By: Crystal Hull Example 3 (Continued): Step 1: First, determine what a and r are.

6 The number a is always the first term of the sequence , so 1a= . The ratio between any term and the one that precedes it should be the same because the sequence is Geometric , so we can choose any pair to find the common ratio r. If we choose the first two terms = Step 2: Since we are given the fourth term, we can multiply it by the common ratio to get the fifth term. 9r= ()5472996561aar= = = Step 3: Now, to find the nth term, substitute 1,9ar= = into the formula for the nth term of a Geometric sequence . ()()()111199nnnnaar == = By: Crystal Hull Example 3 (Continued): Solution (b): Step 1: Calculate a and r.

7 126122613atrtt= = = = Step 2: The fifth term is the fourth term multiplied by the common ratio. Therefore, 5434543162aarttt= = = Step 3: Now, substitute 1,23tar== into the formula for the nth term. 1123nnta = Partial Sums of a Geometric sequence : We can start developing a formula for the sum of the first n terms of a Geometric sequence , , by writing it out in long form. nS ar ararar1 =+ + + ++ By: Crystal Hull Next, we multiply both sides by r. arararar=+ + + ++ We subtract the first result from the second.

8 ()()()()() ar arararrSar ararararrSSar aarararararararar =+ + + ++=+ + + ++ = + + + ++ 1 Using the commutative and associative properties to rearrange the terms on the right, ()()()()( arar arar arar ararara = + + + ++ ) so if , 1r ()()(1) = = Definition: For the Geometric sequence 1nnaar =, the nth partial sum () ar arararr =+ + + ++ is given by 11nnrSar = Written using summation notation, the nth partial sum of a Geometric sequence is 1niikr= . This represents the sum of the first n terms of a Geometric sequence having first term and common ratio r.

9 1akr kr= = By: Crystal Hull Example 4: Find the partial sum of the Geometric sequence that satisfies the given conditions. nS (a) 1,2,7ar n== =(b) 511(8)( )2ii= Solution (a): To find the nth partial sum of a Geometric sequence , we use the formula derived above. Step 1: To use the formula for the nth partial sum of a Geometric sequence , we only need to substitute the given values 1,2,7ar n=== into the formula. ()7711121121 1281127nnrSarS = = = = Solution (b): This is the sum of the first five terms of the Geometric sequence with 1142nna =.

10 Step 1: Since the partial sum is given in summation notation, we must first find a and r. From the given information, we know 18,,52kr n= = =. So, ()121824rakr= = = = By: Crystal Hull Example 4 (Continued): Step 2: Now that we know 14,2ar== , we can substitute these values into the formula for the nth partial sum to find the fifth partial sum. 55112411211324323324323114S = = = = Infinite Series: An expression of the form aa++++ is called an infinite series.


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