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Lecture 16: Projection matrices and least squares
We solve these to find Dˆ = 1/2 and Cˆ = 2/3. We could also have used calculus to find the minimum of the following function of two variables: e2 1 + e 2 2 + e 3 2 = (C + D − 1)2 +(C + 2D − 2)2 +(C + 3D − 2)2. Either way, we end up solving a system of linear equations to find that the closest line to our points is b = 2 3 + 1 2 t ...
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