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Maxima and minima - mathcentre.ac.uk
3(x2 − 1) = 0 ( factorising) 3(x− 1)(x+1) = 0 ( factorising the difference of two squares) It follows that either x − 1 = 0 or x+1 = 0 and so either x = 1 or x = −1. We have found the x coordinates of the points on the graph where dy dx = 0, that is the stationary points.
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