Proof by Contradiction - Gordon College

Proof: p 2 is irrational Proof. Suppose p 2 is rational. Then integers a and b exist so that p 2 = a=b. Without loss of generality we can assume that a and b have no factors in common (i.e., the fraction is in simplest form). Multiplying both sides by b and squaring, we have 2b2 = a2 so we see that a2 is even. This means that a is even (how ...

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