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フェルマー点とシュタイナー点 - tcp-ip USERS CLUB
フェルマー点とシュタイナー点 定理1 三角形abc の外側に三つの正三角形 abp， bcq， car をかくと，その三つの正三角形の 外接円は1 点で交わる． [証明]a b c p q r 60– 60– 60– f120– 120– 120– 図1 円に内接する四角形の相対する内角の和は180°なので， 6 afb = 6 afc = 120– ∴6 bfc = 120–
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3D－GRAPESスクリプト 最初の一歩 - tcp-ip.or.jp
www.tcp-ip.or.jpy=ex 3D－GRAPESスクリプト 最初の一歩 1．3d-grapesとは 3d-grapes は、高校数学の場で広く使われているgrapes の三次元版である。
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