Upper Level SSAT 1500+ Practice Questions Answer Keys ...

1 Upper Level SSAT 1500+ Practice Questions Answer Keys & Explanations Table of Contents Practice Test 1 .. 4 Section 1 Quantitative .. 4 Section 2 Reading .. 5 Section 3 Verbal .. 7 Section 4 Quantitative .. 10 Section 5 Experimental .. 11 Quantitative Reasoning & Mathematics Achievement .. 12 Number Concepts & Operations .. 12 Integers .. 12 12 Fractions .. 13 Percents .. 13 Order of Operations .. 14 Number Theory .. 14 Rules of Divisibility .. 15 Place Value .. 15 Time/Money 15 Estimation .. 16 Unit Analysis .. 16 Computational Clue Problems .. 16 Sequences, Patterns, Logic.

2 17 Algebra .. 17 Common Factor .. 17 Factoring .. 18 Ratio and Proportions .. 18 Word Problems .. 19 Interpreting Variables .. 21 Equations Based on Word Problems .. 21 Equations Based on 22 Rational Expressions .. 22 Exponential Expressions .. 23 Radical Expressions .. 23 Polynomial Expressions .. 24 Linear Equations .. 25 Quadratic Equations .. 26 Inequalities .. 27 Scientific Notation .. 27 Geometry & Measurements .. 28 Pythagorean Theorem .. 28 Perimeter, Area, Volume .. 29 Problems Using Shapes and Angles .. 30 Coordinates .. 31 Transformations .. 31 Slope .. 32 Spatial Reasoning .. 32 Data Analysis & Probability.

3 33 Mean, Median, Mode .. 33 Probability .. 33 Counting .. 34 Set Theory .. 35 Reading Charts & Graphs .. 35 Verbal 36 36 Intermediate .. 38 Advanced .. 39 Verbal Analogies .. 41 Guided Practice Antonyms .. 41 Guided Practice Association .. 42 Guided Practice Cause-and-Effect .. 42 Guided Practice Defining .. 42 Guided Practice Degree/Intensity .. 43 Guided Practice Function/Object .. 43 Guided Practice Grammar .. 44 Guided Practice 44 Guided Practice Noun/Verb .. 44 Guided Practice Part/Whole .. 45 Guided Practice 45 Guided Practice Type/Kind .. 45 Guided Practice Whole/Part.

4 46 Guided Practice Synonym .. 46 Mixed Practice 1 .. 47 Mixed Practice 2 .. 47 Mixed Practice 3 .. 48 Mixed Practice 4 .. 48 Mixed Practice 5 .. 49 Mixed Practice 6 .. 49 Mixed Practice 7 .. 50 Mixed Practice 8 .. 50 Mixed Practice 9 .. 51 Mixed Practice 10 .. 51 Reading Comprehension .. 52 Fiction .. 52 Non-Fiction .. 55 Practice Test 2 .. 60 Section 1 Quantitative .. 60 Section 2 Reading .. 61 Section 3 Verbal .. 64 Section 4 Quantitative .. 66 Section 5 Experimental .. 68 Practice Test 3 .. 68 Section 1 Quantitative .. 68 Section 2 Reading .. 70 Section 3 Verbal .. 73 Section 4 Quantitative.

5 75 Section 5 Experimental .. 77 Practice Test 1 Section 1 Quantitative 1. D. Numbers Fractions. Convert all the fractions to have the lowest common denominator, which is 15. 10 315 + 6 515 3 715 = 13 115. 2. C. Geometry & Measurements Perimeter, Area, & Volume. The hash marks show that the triangle is equilateral, so each side is 12. We can split any equilateral triangle down the middle into two congruent right triangles. Here, each right triangle has a base of 6 and a hypotenuse of 12. We can use the Pythagorean Theorem to find the height, which is 6 3, so the area of the entire triangle is (12)(6 3) = 36 3.

6 3. B. Numbers Percents. We can find the number by applying the formula for percent: 12 = x = 48. 70% of 48 is equal to (48) = 4. C. Data Analysis & Probability Reading Charts & Graphs. The sum of the amounts of money in the account each year is 12,000 + 10,000 + 22,000 + 21,000 + 18,000 = 83,000. The sum divided by the number of years is 83,000 5=16,600, which, rounded to the nearest thousand, is 17,000. 5. D. Geometry & Measurements Problems using Shapes & Angles. The triangle inequality theorem states that a side of a triangle has to be less than the sum of the other two sides, or |a b| < c < a + b. This is only correct for 4 + 6 > 8, 6 + 8 > 4, and 4 + 8 > 6.

7 6. D. Data Analysis & Probability Mean, Median, Mode. Of the prices given, the mode is $15,000. The complete number set, in ascending order, is {$9,000, $12,000, $13,000, $15,000, $15,000, $15,000}. The numbers that are in the middle of this set are $13,000 and $15,000; to find the median, add these 2 numbers and divide by 2. 13000+150002 = 14,000. 7. E. Algebra Interpreting Variables. Each month, Joe s plant grows by 13%, which means times its height is added each month. The plant always has its original height, which is represented by 100%, or 1. Therefore, to find the plant s height after h months, multiply the height by times itself h times.

8 8. E. Algebra Word Problems. This scenario can be represented by the equation s(6 2) = 300. 4s = 300, so x = 75. In context, John will have to sell no fewer than 75 sandwiches to make $300. 9. C. Numbers Estimation. 503663 is close to 500700, which is (simply divide 5 by 7). This is closest to 75%. 10. A. Algebra Interpreting Variables. Simon s cards are represented by x; since Julie has two times as many, she has 2x cards. 11. B. Algebra Ratios & Proportions. We will solve by using a proportion. First, determine which values will be in the numerators and denominators of your ratios. For example.

9 Next set up your proportion: 320 = 12 . Find the cross products: 3 x = 20 12. Then, simplify: 3x = 240, and solve: x = 80 students. There were 80 12 = 68 more students than chaperones. 12. D. Numbers Unit Analysis. There are 176 pints of rice per bag (22 8 = 176). 176 pints 35 bags = 6,160 pints. 13. D. Algebra Quadratic Equations. For the product to be equal to 0, either 3x or x 5 must be equal to 0. So, the only one of the Answer choices that will work in the equation is 5. 14. A. Algebra Linear Equations. Distribute 5 over (x + ) which yields 5x + = 5x + 12. Subtract 5x from both sides of the equation which will result in = 12.

10 This is a false statement since 12. Hence, there is no solution or 0 solutions. 15. A. Algebra Inequalities. To solve the inequality, or find its possible solutions, multiply both sides of the inequality by 3. 16. A. Geometry & Measurements Pythagorean Theorem. The area of each square is the length of one side squared (s2). Based on the information given in the problem, we know from the Pythagorean Theorem that a2 + b2 = 64 + 17. Therefore, c2 = 81. Since c2 = x2, x2 = 81 and x = 9. 17. E. Numbers Sequences, Patterns, Logic. 100 is evenly divisible by 7 only 14 times. This means that we can get from 100 down 14 7 = 98 places, to 2, before going negative.