version 1.0 Solved Examples - SoFA

1 SoFA version Nikolaou Dimitris PitilakisShallOw Foundation Analysis SoftwareAristotle University of ThessalonikiThessaloniki 2012 Solved ExamplesSoFA Solved Examples Konstantinos Nikolaou Dimitris Pitilakis ShallOw Foundation Analysis software Aristotle University of Thessaloniki Thessaloniki 2013 SoFA: Shallow Foundation Analysis software Solved Examples 2 Contents Contents .. 2 Acknowledgements .. 3 Introduction .. 3 example # 1 Rectangular foundation - Cohesive soil .. 4 example # 2 Rectangular Foundation Cohesionless soil.

2 8 example # 3 Foundation on Cohesionless soil .. 13 example # 4 Earthquake Bearing Capacity .. 18 example # 5 Settlement Calculation .. 23 Further Reading .. 27 Appendix - List of symbols .. 28 SoFA: Shallow Foundation Analysis software Solved Examples 3 Acknowledgements We thank Prof. Christos Anagnostopoulos from the Dept. of Civil Engineering of AUTh for the scientific guidance. We thank Konstantinos Trevlopoulos (AUTh) for his very useful remarks. Also we thank Ivan Kraus (University of Osijek) for his comments and for the contribution of the symbols list and the third Solved example .

3 Introduction This manual contains Solved Examples that were used to validate SoFA For an advanced description of the algorithms and formulas used, consult the analytical user s manual. If you discover what you think is a bug, report it here. Please try to include all SoFA reports. ! All loads are considered to act at the base of the footing and NOT at the theoretical point of column fixity (for more information check out the analytical users' manual). SoFA does NOT calculate the footing self weight. SoFA: Shallow Foundation Analysis software Solved Examples 4 example # 1 Rectangular foundation - Cohesive soil Calculate the ultimate static bearing capacity of the shallow foundation depicted in fig.

4 1. Figure 1 x= y = m & y= x = m x = 2 x=2 2 m y = y 2 y=4 2 m =min Bx ,By = m & = Lx ,Ly = m < = + + =19 1+18 2 1 +0=37 kPa For cohesive soils under undrained loading conditions according to Eurocode 7: = . + c= 1 + = 1 + = x2+ y2 = 202+1002=102 kN c=12+12 1 u=12+12 1 100= = 100 1+37= kPa = = kN SoFA: Shallow Foundation Analysis software Solved Examples 5 Calculation performed using SoFA: Figure 2 Click the Bearing Capacity button to access window showing the Safety Factory for Static Load Case: Figure 3 SoFA.

5 Shallow Foundation Analysis software Solved Examples 6 Shallow Foundation Bearing Capacity ---------------------------------------- --------------------- Kostis Nikolaou Dimitris Pitilakis Aristotle University of Thessaloniki - 2012 ---------------------------------------- --------------------- Geometry of the problem * Dimentions(dx/dy) = x [m] * Depth of foundation (df) = [m] * Depth of water level(dw) = [m] * Foundation base inclination(omega) = [rad.] * Soil inclination(beta) = [rad.] Design Loads - Static Load Case * Vd = [kN] * Hdx = [kN] * Hdy = [kN] * Mdx = [kNm] * Mdy = [kNm] Soil Properties * Type = C [C: cohessive CL: cohesionless] * Loading= UN [D: drained UN: undrained] * phik = [deg.]

6 ] * ck = [kPa] - drained shear strength * cuk = [kPa] - undrained shear strength * soil Weight = [kN/m^3] ======================================== ===================== Eccentricities (Static Load Case): ex = ey = [m] Effective Dimentions: x [m] Effective Area: [m^2] ---------------------------------------- --------------------- Bearing Capacity Check -- Undrained Conditions -- Static Load Case ---------------------------------------- --------------------- * Eurocode 7 (2004) sc= | ic= | bc= | - qu_un = [kPa] - Vu = qu*B*L = [kN] - = qu*B* = [kN] < [kN] - NOT ok - - FS = qu/N*Aeff = * EAK (2000)

7 Sc= | ic= | - qu_un = [kPa] - Vu = qu*B*L = [kN] - qu*B* = [kN] < [kN] - NOT ok - - FS = qu/N*Aeff = * DIN4017 (2006) sc= | ic= | bc= | gc= | - qu_un = [kPa] - Vu = qu*B*L = [kN] SoFA: Shallow Foundation Analysis software Solved Examples 7 - qu*B* = [kN] < [kN] - NOT ok - - FS = qu/N*Aeff = * Meyerhof (1953,1963) sc= | ic= | dc= | sq= | iq= | dq= | - qu_un = [kPa] - Vu = qu*B*L = [kN] - qu*B* = [kN] < [kN] - NOT ok - - FS = qu/N*Aeff = * Hansen (1970) sc= | ic= | bc= | gc= | dc= | - qu_un = [kPa] - Vu = qu*B*L = [kN] - qu*B* = [kN] < [kN] - NOT ok - - FS = qu/N*Aeff = SoFA.

8 Shallow Foundation Analysis software Solved Examples 8 example # 2 Rectangular Foundation Cohesionless soil Calculate the ultimate static bearing capacity of the shallow foundation depicted in fig. 2. Figure 4 x= y = m & y= x = m x = x 2 x=2 2 m y = y 2 y=2 2 m =min Bx ,By = & = Lx ,Ly = m < < + = = + . = f+ =18 1+19 1+0=37 kPa = w f + sat w f+ w =19 2 + 20 10 (2+ ) kN/m3 For cohesionless soils under drained loading conditions, according to Eurocode 7: u= c c c c+ q q q q+12 =tan2 4+ 2 = 2 4+352 35= =2 q 1 =2 1 35= =1+ =1+ 35= SoFA.

9 Shallow Foundation Analysis software Solved Examples 9 = 1 =1 = x2+ y2 = + = cos2 + sin2 = =2+ / 1+ / = & =2+ / 1+ / = q= 1 + = 1 +0 = 1 + +1= 1 +0 bq=b = 1 2= u=0+ 1 18+1 19 +12 0683= kPa u= u = kN Calculation performed using SoFA: Figure 5 Click the Bearing Capacity button to access the windows showing the Safety Factory for Static Load Case and the Ultimate Bearing Capacity: SoFA: Shallow Foundation Analysis software Solved Examples 10 Figure 6 Figure 7 SoFA.

10 Shallow Foundation Analysis software Solved Examples 11 Shallow Foundation Bearing Capacity ---------------------------------------- --------------------- Kostis Nikolaou Dimitris Pitilakis Aristotle University of Thessaloniki - 2012 ---------------------------------------- --------------------- Geometry of the problem * Dimentions(dx/dy) = x [m] * Depth of foundation (df) = [m] * Depth of water level(dw) = [m] * Foundation base inclination(omega) = [rad.] * Soil inclination(beta) = [rad.] Design Loads - Static Load Case * Vd = [kN] * Hdx = [kN] * Hdy = [kN] * Mdx = [kNm] * Mdy = [kNm] Soil Properties * Type = CL [C: cohessive CL: cohesionless] * Loading= D [D: drained UN: undrained] * phik = [deg.]