Worksheet 3 6 Arithmetic and Geometric Progressions

1 Worksheet3:6 ArithmeticandGeometricProgressionsSectio n1 ArithmeticProgressionAnarithmeticprogres sionis a listof numberswherethedi erencebetweensuccessive numbersis constant. Thetermsin an arithmeticprogressionareusuallydenotedas u1; u2; theinitialtermin theprogression,u2is thesecondterm,andso on;unis thenth anarithmeticprogressionis2;4;6;8;10;12;1 4; : : :Sincethedi erencebetweensuccessive termsis constant, we haveu3 u2=u2 u1andin generalun+1 un=u2 u1We willdenotethedi erenceu2 u1asd, which is a : Giventhat3,7and11arethe rstthreetermsin anarithmeticprogression,whatisd?7 3 = 11 7 = 4 Thend= 4. Thatis, thecommondi erencebetweenthetermsis we know the rsttermin anarithmeticprogression, andthedi erencebetweenterms,thenwe canworkoutthenth term, canworkoutwhatany termwillbe. Theformulawhichtellsus whatthenth termin anarithmeticprogressionisun=a+ (n 1) dwhereais the : If the rst3 termsin anarithmeticprogressionare3,7,11thenwhat is the10thterm?The rsttermisa= 3, andthecommondi erenceisd= + (n 1)du10=3 + (10 1)4=3 + 9 4=391 Example3: If the rst3 termsin anarithmeticprogressionare8,5,2thenwhati sthe16thterm?

2 In thisprogressiona= 8 andd= + (n 1)du16=8 + (10 1) ( 3)= 37 Example4: Giventhat2x;5 and6 xarethe rstthreetermsin anarithmeticprogression, whatisd?5 2x=(6 x) 5x=4 Sincex= 4, thetermsare8, 5, 2 andthedi erenceis 3. Thenexttermin thearithmeticprogressionwillbe can ndthesumof the rstnterms,which we willdenotebySn, usinganotherformula:Sn=n2[2a+ (n 1)d]Example5: If the rst3 termsin anarithmeticprogressionare3,7,11thenwhat is thesumof the rst10 terms?Notethata= 3,d= 4 andn= (2 3 + (10 1) 4)=5(6+ 36)=210 Alternatively, butmoretediously, we addthe rst10 termstogether:S10= 3 + 7 + 11 + 15 + 19 + 23 + 27 + 31 + 35 + 39 = 210 Thismethod wouldhave drawbacks if we hadto add100termstogether!Example6: If the rst3 termsin anarithmeticprogressionare8,5,2thenwhati sthesumof the rst16 terms?S16=162(2 8 + (16 1) ( 3))=8(16 45)= 2322 Exercises:1. For each of thefollowingarithmeticprogressions, ndthevaluesofa,d, andtheunindicated.(a)1, 4, 7,: : :, (u10)(b) 8, 6, 4,: : :, (u12)(c)8, 4, 0,: : :, (u20)(d) 20, 15, 10,: : :, (u6)(e)40,30,20,: : :, (u18)(f) 6, 8, 10,: : :, (u12)(g)2, 212, 3,: : :, (u19)(h)6, 534, 512,: : :, (u10)(i) 7, 612, 6,: : :, (u14)(j)0, 5, 10,: : :, (u15)2.

3 For each of thefollowingarithmeticprogressions, ndthevaluesofa,d, andtheSnindicated.(a)1, 3, 5,: : :, (S8)(b)2, 5, 8,: : :, (S10)(c)10,7, 4,: : :, (S20)(d)6, 612, 7,: : :, (S8)(e) 8, 7, 6,: : :, (S14)(f) 2, 0, 2,: : :, (S5)(g) 20, 16, 12,: : :, (S4)(h)40,35,30,: : :, (S11)(i)12,1012, 9,: : :, (S9)(j) 8, 5, 2,: : :, (S20)Section2 GeometricProgressionsA geometricprogressionis a listof termsas in anarithmeticprogressionbutin thiscasetheratioof successive termsis a constant. In otherwords,each termis a constant 'swritethetermsin a geometricprogressionasu1; u2; u3; u4andso a geometricprogressionis10;100;1000;10000; : : :Sincetheratioof successive termsis constant, we haveu3u2=u2u1andun+1un=u2u1 Theratioof successive termsis usuallydenotedbyrandthe rsttermagainis : Findrforthegeometricprogressionwhose rstthreetermsare2, 4, 2 Thenr= : Findrforthegeometricprogressionwhose rstthreetermsare5,12, 5 =120 12=110 Thenr= we know the rsttermin a geometricprogressionandtheratiobetweensu ccessive terms,thenwe canworkoutthevalueof any termin thegeometricprogression.

4 Thenthtermisgivenbyun=arn 1 Again,ais the rsttermandris thatarn 16= (ar)n : Given the rsttwo termsin a geometricprogressionas 2 and4, whatis the10thterm?a= 2r=42= 2 Thenu10= 2 29= : Given the rsttwo termsin a geometricprogressionas 5 and12, whatis the7thterm?a= 5r=110 Thenu7=5 (110)7 1=51000000=0:0000054A geometricseriesis a a geometricseriesis1 +110+1100+11000+ We cantake thesumof the rstntermsof a geometricseriesandthisis denotedbySn:Sn=a(1 rn)1 rExample5: Given the rsttwo termsof a geometricprogressionas 2 and4, whatis thesumof the rst10 terms?We know thata= 2 andr= 2. ThenS10=2(1 210)1 2=2046 Example6: Given the rsttwo termsof a geometricprogressionas 5 and12, whatis thesumof the rst7 terms?We know thata= 5 andr=110. ThenS7=5(1 1107)1 110=51 1107910=5:555555In certaincases,thesumof thetermsin a geometricprogressionhasa limit(notethatthisissummingtogetheranin nitenumber of terms).A serieslike thishasa limitpartlybecauseeach successive termwe areaddingis smallerandsmaller(butthisfactin itselfis notenoughto say thatthelimitingsumexists).

5 Whenthesumof a geometricserieshasa limitwe saythatS1existsandwe can ndthelimitof moreinformationonlimits, thatris greaterthan 1 butlessthan1, <1. If thisis thecase,thenwe canusetheformulaforSnabove andletngrow arbitrarilybigso thatrnbecomesas closeas we like to ris thelimitof thegeometricprogressionso longas 1< r < : Thegeometricprogressionwhose rsttwo termsare2 and4 does nothave aS1becauser= 26< : For thegeometricprogressionwhose rsttwo termsare5 and12, ndS1. Notethatr=110sojrj<1, so r=51 110=559 Sothesumof 5 +12+120+1200+: : :is 559 Example9: Considera geometricprogressionwhose rstthreetermsare12, 6and3. Noticethatr= 12. (1 rn)1 r=12(1 ( 12)8)1 ( 12) 7:967S1=a1 r=121 ( 12)=123=2=8 Exercises:1. Findthetermindicatedforeach of thegeometricprogressions.(a)1, 3, 9,: : :, (u9)(b)4, 8, 16,: : :, (u10)(c)18, 6, 2,: : :, (u12)(d)1000,100,10,: : :, (u7)(e)32, 8, 2,: : :, (u14)(f) 0:005, 0:05, 0:5,: : :, (u10)(g) 6, 12, 24,: : :, (u6)(h)1:4, 0:7, 0:35,: : :, (u5)(i)68, 34,17,: : :, (u9)(j)8, 2,12,: : :, (u11)62.

6 Findthesumindicatedforeach of thefollowinggeometricseries(a)6 + 9 + 13:5 + (S10)(b)18 9 + 4:5 + (S12)(c)6 + 3 +32+ (S10)(d)6000+ 600+ 60 + (S20)(e)80 20 + 5 + (S9) For each of thefollowingprogressions,determinewhethe rit is Arithmetic , Geometric ,orneither:(a)5, 9, 13,17,: : :(b)1, 2, 4, 8,: : :(c)1, 1, 2, 3, 5, 8, 13,21,: : :(d)81, 9, 3,13,: : :(e)512,474,436,398,: : :2. Findthesixthandtwentiethterms,andthesumo f the rst10termsof each of thefollowingsequences:(a) 15, 9, 3,: : :(b)log7, log14,log28,: : :(c)116,18,14,: : :(d) , , ,: : :(e)64, 32,16,: : :3.(a)Thethirdandeighthtermsof anAPare470and380respectively. Findthe rsttermandthecommondi : writeexpressionsforu3andu8andsolvesimult aneously.(b)Findthesumto 5 termsof thegeometricprogressionwhose rsttermis 54andfourthtermis 2.(c)Findthesecondtermof a geometricprogressionwhosethirdtermis94an dsixthtermis 1681.(d)Findthesumtontermsof anarithmeticprogressionwhosefourthand fthtermsare13 (a)A university lecturerhasanannualsalaryof $40, thisincreasesby 2%eachyear,how much willshehave grossedin totalafter10 years?

7 (b)A bobof a pendulumswingsthroughanarcof 50cmonits swingis 90%of thelengthof (a) Arithmetic (b) Geometric (c)Neither(d)Ne ither(e)Arithmetic2.(a)T6= 15,T20= 99,S10= 120(b)T6= log7 + 5 log2,T20= log7 + 19 log2,S10=102(2 log7 + 9 log2)(c)T6= 2,T20= 215,S10=116(210 1)(d)T6= (0:5)(0:9)5,T20= (0:5)(0:9)19,S10= 5(1 :910)(e)T6= 2,T20= 1213,S10=1283(1 + 2 10)3.(a)a=506,d= 18(b)81(1 (13)5)(c)T2= (94)3(d)n2+ 6n4.(a)$437, (b)5 metres9