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Likelihood Ratio Tests - Missouri State University
people.missouristate.edudistribution. We can look at the chi-square table under 10 degrees of freedom to flnd that 3.94 is the value under which there is 0.05 area. Using this, we can obtain P(2 2 P Xi • 3:94) = 0:05. This implies that we should reject the null hypothesis if P Xi • 3:94 in this example.