Transcription of 章発振回路 - ieice-hbkb.org
{{id}} {{{paragraph}}}
1 -7 -4 . 1 -- 7 . 4 . 2011 10 .. 6 6-4 .. 4-1 . 4-2 4-3 .. c 2011 1/(9). 1 -7 -4 . 1 -- 7 -- 4 . 4 -- 1 . 2009 12 . 4 -- 1 -- 1 .. 4 1 . Ecut . 0 . V2 /V1 T (j2 f ) = V2 /V1 V1 . V2 . f VA f V1 = VA f cos (2 f t) . V2 = |T (j2 f )|VA f cos (2 f t + T (j2 f )) f0 . |T (j2 f0 )| = 1 T (j2 f0 ) = 0 V2 = VA f cos (2 f0 t) . f = f0 T (j2 f ) 1 0 Ecut f0 . Ecut Ecut . Vout = VA f cos (2 f0 t) T (j2 f ) |T (j2 f0 )| 1. T (j2 f0 ) = 0 .. 1 . 4 1 . 4 -- 1 -- 2 . 4 2 Zi i = 1 2 3 Xi . Zi = jXi X1 + X2 + X3 = 0 X1 /X3 gm rd Z1 Z3 Z2. c 2011 2/(9).
電子情報通信学会『知識の森』(http://www.ieice-hbkb.org/) 1 群-7編-4章 となるその狭い帯域内でのみ発振が可能である.二つの ...
Domain:
Source:
Link to this page:
Please notify us if you found a problem with this document:
{{id}} {{{paragraph}}}