Linear Transformation Exercises
Here, by de nition we have that T(~e 1) = T 1 0 = 2 4 1 0 4 3 5;T(~e 2) = T 0 1 = 2 4 1 3 5 3 5 Thus, A = 2 4 1 1 0 3 4 5 3 5 3 (b) T : R2!R2, satisfying T 1 1 = 1 2 ;T 2 3 = 2 5 Solution: We need to nd T(~e 2) and T(~e 2). Given the information we have, this is easiest to do by writing ~e 1 and ~e 2 as linear combinations of ˆ 1
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