source transformations - Iowa State University
20 V 7.5 kΩ 2 mA Transform the voltage source / ... 1 kΩ 15 mA 40 V 1 kΩ 1 kΩ 15 V Writing a KVL loop equation and solving for i R1 gives L5 = 96 967 5 + 5 = 9 9 N |+ N | This is the correct answer. = . P$ EE 201 source transformations – 8
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