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Version 001 – EXAM 7 PRACTICE PROBLEMS – chemistry ...

4.3.95 kJ released 5.3.95 kJ absorbed 6.0.253 kJ released Explanation: MW CH3OH = 32.042g ∆H(fusion) = −∆H(freezing) q = 25.6 g × 1mol 32.042g × −3.16 kJ mol = −2.525 kJ 003 10.0points A 0.2 gram sample of a candy bar is com-busted in a bomb calorimeter, increasing the temperature of the 2000 g of water from 25.00 C to 25.47 C. What ...

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