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Math 430 { Problem Set 5 Solutions
math.mit.eduWe show that these are both well de ned ring homomorphisms. In both cases, adding a multiple of 6 to nchanges the result by a multiple of 15 (0 in the rst case and 60 in the second), so they are well de ned. They are additive group homomorphisms by the distributive law in Z 15. They are multiplicative since 0 0 = 0 (10n) (10m) = 100nm= 10nm: 16.10.
RING HOMOMORPHISMS AND THE ISOMORPHISM …
sites.math.washington.edu1. Kernel, image, and the isomorphism theorems A ring homomorphism ’: R!Syields two important sets. De nition 3. Let ˚: R!Sbe a ring homomorphism. The kernel of ˚is ker˚:= fr2R: ˚(r) = 0gˆR and the image of ˚is im˚:= fs2S: s= ˚(r) for some r2RgˆS: Exercise 9. Let Rand Sbe rings and let ˚: R!Sbe a homomorphism. Prove that ˚is