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Math 430 { Problem Set 5 Solutions
math.mit.eduWe show that these are both well de ned ring homomorphisms. In both cases, adding a multiple of 6 to nchanges the result by a multiple of 15 (0 in the rst case and 60 in the second), so they are well de ned. They are additive group homomorphisms by the distributive law in Z 15. They are multiplicative since 0 0 = 0 (10n) (10m) = 100nm= 10nm: 16.10.