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Impulse and Momentum - bowlesphysics.com

AP Physics BImpulse and MomentumImpulse = MomentumConsider Newton s 2ndLaw and the definition of accelerationUnits of Impulse : Units of Momentum : Momentum is defined as Inertia in Motion NsKg x m/sExampleA 100 g ball is dropped from a height of h = m above the floor. It rebounds vertically to a height of h'= m after colliding with the floor. (a) Find the Momentum of the ball immediately before it collides with the floor and immediately after it rebounds, (b) Determine the average force exerted by the floor on the ball. Assume that the time interval of the collision is seconds. * *22212====== * *22=====smkgpsmkgpvmpafterbefore/* ) ( * ) ( = = = )) ( ( ) ()(= = = = Impulse is the AreaSince J=Ft, Impulse is the AREA of a Force vs. Time graph. How about a collision?Consider 2 objects speeding toward each other.

Impulse is the Area Since J=Ft, Impulse is the AREA of a Force vs. Time graph.

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Transcription of Impulse and Momentum - bowlesphysics.com

1 AP Physics BImpulse and MomentumImpulse = MomentumConsider Newton s 2ndLaw and the definition of accelerationUnits of Impulse : Units of Momentum : Momentum is defined as Inertia in Motion NsKg x m/sExampleA 100 g ball is dropped from a height of h = m above the floor. It rebounds vertically to a height of h'= m after colliding with the floor. (a) Find the Momentum of the ball immediately before it collides with the floor and immediately after it rebounds, (b) Determine the average force exerted by the floor on the ball. Assume that the time interval of the collision is seconds. * *22212====== * *22=====smkgpsmkgpvmpafterbefore/* ) ( * ) ( = = = )) ( ( ) ()(= = = = Impulse is the AreaSince J=Ft, Impulse is the AREA of a Force vs. Time graph. How about a collision?Consider 2 objects speeding toward each other.

2 When they Due to Newton s 3rdLaw the FORCE they exert on each other are EQUAL and TIMES of impact are also , the IMPULSES of the 2 objects colliding are also EQUAL21212121)()(JJFtFtttFF = == =How about a collision?If the Impulses are equal then the MOMENTUMS are also equal!2222111122211122112121)()(oooovmvm vmvmvvmvvmvmvmppJJ+ = = = = =22112211vmvmvmvmppooafterbefore+=+= Momentum is conserved!The Law of Conservation of Momentum : In the absence of an external force (gravity, friction), the total Momentum before the collision is equal to the total Momentum after the collision. smkgpsmkgpsmkgpsmkgpsmkgpsmkgmvptotalcar trucktotalocarootrucko/*3300/* *400/*15003*500/*3300/*800)2)(400(/*2500 )5)(500()()()(===========Several Types of collisionsSometimes objects stick together or blow apart.

3 In this case, Momentum is ALWAYS )(0220112211022011vmvmvmvmvmvmvmvmvmvmpp totalototaltotaltotalafterbefore+==++=+= When 2 objects collide and DON T stickWhen 2 objects collide and stick togetherWhen 1 object breaks into 2 objectsElasticCollision = Kinetic Energy isConservedInelasticCollision = Kinetic Energy is NOTC onserved ExampleA bird perched on an cm tall swing has a mass of g, and the base of the swing has a mass of 153 g. Assume that the swing and bird are originally at rest and that the bird takes off horizontally at m/s. If the base can swing freely (without friction) around the pivot, how high will the base of the swing rise above its original level?How many objects due to have BEFORE the action?How many objects do you have AFTER the action?12=+=+==swingswingToTABvvvmvmvmpp )2)( () ()0)( ()( m/s====== ) (221222)( mExampleGranny (m=80 kg) whizzes around the rink with a velocity of 6 m/s.

4 She suddenly collides with Ambrose (m=40 kg) who is at rest directly in her path. Rather than knock him over, she picks him up and continues in motion without "braking." Determine the velocity of Granny and many objects do I have before the collision?How many objects do I have after the collision?21==+=+=TTTT ooabvvvmvmvmpp120)0)(40()6)(80(22114 m/sCollisions in 2 DimensionsThe figure to the left shows a collision between two pucks on an air hockey table. Puck A has a mass of and is moving along the x-axis with a velocity of + m/s. It makes a collision with puck B, which has a mass of and is initially at rest. The collision is NOT head on. After the collision, the two pucks fly apart with angles shown in the drawing. Calculate the speeds of the pucks after the vAsin vBcos vBsin Collisions in 2 dimensionsvAvBvAcos vAsin vBcos vBsin )37cos)(050(.

5 65cos)(025(.0) )( (BAxBBxAAoxBBoxAAxoxvvvmvmvmvmpp+=++=+= += )37sin)( ()65sin)( (00== +=+== Collisions in 2 ) )( ( +=+= += ) ()


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