Example: barber
Multiple knapsack problem - unibo.it
158 6 0-1 Multiple knapsack problem Pj and Ci are positive integers, F.5) Wj < max;gM{c/} for j EN, F.6) Ci > minyg/v{vvy} for i EM, F.7) n y^vvy > c; for / G M. F.8) If assumption F.5) is violated, fractions canbe handled by multiplying through by a proper factor, while nonpositive values can easily be handled by eliminating all items with pj < 0 and all knapsacks with c; < 0. (There is no ...
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