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Solved Electricity numerical for class 10
10.Calculate the power rating of the heater coil when used on 220V supply taking 5 Amps. Solution: Voltage ,V = 220V and Current ,I = 5A, Power, P = VI = 220 × 5 = 1100W = 1.1 KW. 11.A lamp can work on a 50 volt mains taking 2 amps.What value of …
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jsuniltutorial.weebly.comSolved Electricity numerical for class 10 1. Question: Two bulbs have ratings 100 W, 220 V and 60 W, 220 V respectively. Which one has a greater resistance? Answer: P=VI= V2/R For the same V, R is inversely proportional to P. Therefore, the bulb 60 W, 220 V has a greater resistance. 2. Question: A torch bulb has a resistance of 1 Ω when cold.
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