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Chapter 4: Solution Stoichiometry – Cont.

Chapter 4: Solution Stoichiometry – Cont.

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Tro: Chemistry: A Molecular Approach, 2/e 1 L Pb(NO 3)2 = 0.175 mol, 1 L KCl = 0.150 mol, 1 mol Pb(NO 3)2: 2 mol KCl Solution: 16 Tro: Chemistry: A Molecular Approach, 2/e Example 4.8 – Cont. Answer: 0.350 L or 350 mL of 0.150 M KCl is needed for the reaction

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