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16.31 Homework 1 Solution - MIT
Solution: The equation can be rewritten as s3 +5s2 +6s+K s2 +s+2 = 0 This equation is essentially the characteristic equation for a system with open-loop zeros at the roots of s2 + s + 2 = 0 and open-loop poles at the roots of s3 + 5s2 + 6s = 0. So the zeros are at z 1,2 = − 1 2 ±j √ 7 2 ≈ −0.5±1.3229j The poles are at p 1 = 0 p 2 ...
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