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The mesh-current method - Iowa State University
EE 201 mesh-current method – 11 The mesh current method 1. Identify all of the individual meshes in the circuit. 2. Assign a mesh current to each mesh. Identify meshes in which the current is known because there is a current source in an outside branch of the mesh. 3. Assign voltages to all of the elements in the meshes with unknown currents. 4.
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Thevenin equivalent circuits - Iowa State University
tuttle.merc.iastate.eduJun 10, 2014 · The open-circuit voltage / short-circuit current approach can be used to calculate the Thevenin equivalent for a known circuit. Consider the circuit from slide 4: + – V S R 1 R 2 I S 9V 6 mA 1.5 k! 3 k! Open-circuit voltage – Use whatever method you prefer. We’ll use node voltage in this case. + – V S R 1 R 2 I S v a + – v oc YRF= YD ...
npn Bipolar Junction Transistor - Iowa State University
tuttle.merc.iastate.edujunction — very surprising! EE 436 BJT currents – 6 The electron current in the base is determined by the boundary ... External (terminal) currents. All currents depend on V BE in exactly the same way. Although it is a messy exponential, they …
Basic PMOS structure - Iowa State University
tuttle.merc.iastate.eduohmic or linear v GS < V T v DS < v GS – V T i D = K[v GS – V T]2 saturation Summary of PMOS equations K = 1 2 μCox W L VT < 0 Note the equations are identical to the NMOS equations. For a PMOS, v GS and v DS are both negative and the current flows from source to drain.
Solving circuits directly using Laplace
tuttle.merc.iastate.eduAnalyze the circuit in the time domain using familiar circuit analysis techniques to arrive at a differential equation for the time-domain quantity of interest (voltage or current). 2. Perform a Laplace transform on the differential equation to arrive a ... C in the RLC circuit below. The input is a step function, v i ...
pspice op amp - Iowa State University
tuttle.merc.iastate.eduThis tutorial is written with the assumption that you know how to do ... So it looks like the uA741 model has the potential to be a reasonably accurate PSPICE op amp
How Millennials Can Get Rich Slowly
tuttle.merc.iastate.eduHow Millennials Can Get Rich Slowly William J. Bernstein ©2014 . Would you believe me if I told you that there’s an investment strategy that a seven-year-old could ... and vigor, your retirement options may well range between moving in with your kids and sleeping under a bridge in the rain.
First-order filters - Iowa State University
tuttle.merc.iastate.eduFirst-order filters The general form for the transfer function of a first order filter is: T(s) = G o ... Use the standard definition for cut-off frequency, which is the frequency at which the magnitude is down by from the value in the pass-band. For our low-pass function, the pass band is at low frequencies, and the ...
Rectifier circuits & DC power supplies
tuttle.merc.iastate.eduNov 01, 2015 · Rectifier circuits & DC power supplies Goal: Generate the DC voltages – needed for most electronics – starting with the AC power that comes through the power line.? 120 V RMS 9DF=( 9)sin 7 W f = 60 Hz (T = 16.67 ms) How to take time-varying voltage with an average value of 0 and turn it into a DC voltage?
Series and parallel combinations
tuttle.merc.iastate.eduEE 201 series/parallel combinations – 12 Breaking down networks using series and parallel R 3 R 4 R 5 R eq R 2 But not all circuits are simple R 1 combinations of series or parallel resistors. The initial example circuit clearly has some things that are in series and some elements that have a parallel-type connection.
superposition - Iowa State University
tuttle.merc.iastate.eduEE 201 superposition – 2 2va + 6vb = 2V 8va 2vb = 36V Solving gives: v a = 5 V, v b = 2 V 8v a 2v b = 0 2v a + 6v b = 2V Solving gives: and 2v a + 6v b = 0 8v a 2v b = 36V A math problem: Mathematically, we can solve the simultaneous equations a piece at a
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cktse.eie.polyu.edu.hkMesh analysis Step 1: Define meshes and unknowns Each window is a mesh. Here, we have two meshes. For each one, we “imagine” a current circulating around it. So, we have two such currents, I1 and I2 — unknowns to be found. Step 2: Set up KVL equations Step 3: Simplify and solve which gives I1 = 6 A and I2 = 4 A. Once we know the mesh ...
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