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Version 001 – EXAM 7 PRACTICE PROBLEMS – chemistry ...
Version 001 – EXAM 7 PRACTICE PROBLEMS – chemistry – (78712) 2 7.−680 kJ/mol Explanation: ∆H0 rxn = X BEreactants− X BE products = (C C)+ 4 (C H) +3 (O O) − 4 (C O)+4 (H O) = 602 kJ mol + 4 413 kJ mol +3 498 kJ mol − 4 799 kJ mol +4 463 kJ mol = −1300 kJ mol 005 10.0points Methyl tert-butyl ether or MTBE is an oc-tane booster ...
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